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tia_tia [17]
4 years ago
14

As ocean waves approach shore, their velocity decreases. How does a decrease in velocity affect the frequency and wavelength of

the waves entering the shallow water?
Physics
1 answer:
Rashid [163]4 years ago
4 0
A decrease in velocity also causes a decrease in frequency and wavelength because if we manipulate the equation: v = f × wavelength, we can see that:

f = v / wavelength

wavelength = v / f

So in both cases the velocity is on the top. If the velocity decreases by a half for example then the wavelength and frequency will both decrease by a half because the velocity is proportional to the two values.
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Which of the physical variables listed below will change when you change the area of the capacitor plates (while keeping the bat
RSB [31]

Answer:

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

Explanation:

Let A be the area of the capacitor plate

The capacitance of a capacitor is given as;

C = \frac{Q}{V} = \frac{\epsilon _0 A}{d} \\\\

where;

V is the potential difference between the plates

The charge on the plates is given as;

Q = \frac{V\epsilon _0 A}{d}

The energy stored in the capacitor is given as;

E = \frac{1}{2} CV^2\\\\E = \frac{1}{2} (\frac{\epsilon _0 A}{d} )V^2

Thus, the physical variables listed that will change include;

a. Capacitance

b. Charge on the plates  

e. Energy stored in the capacitor

3 0
3 years ago
A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this
borishaifa [10]

Answer:

-1.2×10^2 m

I hope this helps you

4 0
3 years ago
A 6.11-g bullet is moving horizontally with a velocity of 366 m/s, where the sign indicates that it is moving to the right (see
jeka94

Answer:

V=1.86m/s

Explanation:

Mass of bullet M_B=6.11g

Velocity of bullet V_B=366m/s

Mass of first block M_b_1=1206g

Velocity of block V_b=0.662m/s

Mass of second block M_b_2=1550g

Generally the total momentum before collision is mathematically given as

P_1=0.006kg*366+0+0

P_1=2.196kg\ m/s

Generally the total momentum after collision is mathematically given as

P_2=(1.206kg*0.633)+(1.550+0.00611)V

P_2=0.763398+1.55611V

Generally the total momentum is mathematically given as

P_1=P_2

2.196=0.763398+1.55611V

V=\frac{2.196+0.763398}{1.55611}

V=1.86m/s

4 0
3 years ago
You are in a fire truck heading directly toward a tunnel in a mountainside at 17m/s. you hear the truck's 90Hz siren as well as
Kryger [21]

Hey there!:

Take the speed of sound to be 343m/s.

Direct frequency perceived by observer:

(343 + 17) / 343) * 90Hz = 94.460Hz

Change in frequency = ( 4.460 - 90 ) = 4.460Hz.  

90 - (4.460 x 2) = 81.08 Hz. indirect frequency heard by observer.  

Therefore :

Beat frequency = (94.460 - 81.08) = 13.38Hz.  

Hope this helps!

4 0
3 years ago
Witch statement about electric force is true?
Wewaii [24]
Please give me the statement :)
6 0
3 years ago
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