Question

Which shows the graph of the solution set of 6x + 3y ≤ 12?

Answer 1

$y \leqslant - 2x + 4$
because you have to subtract 6 and bring it to the other side then divide by three on all numbers which should get you that

Answer 2

Answer with explanation:

The given inequality in two variables is

 ⇒ 6 x + 3 y ≤ 12

⇒3×(2 x +y)≤ 3 × 4

Cancelling,3 from, both sides of the equation

⇒ 2 x + y ≤ 4

Writing the above linear inequality in slope intercept form of line

 $\rightarrow\frac{2 x}{4}+\frac{ y}{4}\leq 1\\\\\rightarrow\frac{ x}{2}+\frac{ y}{4}\leq 1$

Putting, x=0, and ,y=0 in the above inequality , to check origin lies on which side of inequality

→0+0≤ 4

→0≤ 4

Solution set will include the origin and will be on the left of line and will include the line, 2 x +y≤ 4 also.