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3 years ago

Please help me solve this problem

Mathematics

1 answer:

Alla [95]3 years ago

8 0

Answer:

Option B , D and E are correct.

Step-by-step explanation:

We set the denominator equal to zero to find the number to put in division box

So, if 3 is in the division box then the denominator will be

x-3 = 0 => x=3 is the root.

So, Option E is correct

2x^2-2x-12 ÷ x-3 = 2x+4 is correct.

because after division the result given is 2x+4 which is correct.

So, Option B is correct

x-3 is a factor of 2x^2-2x-12 because because when the term is divided we get the remainder 0.

So, Option D is correct

So, Option B,D and E are correct.

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Answer:

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Step-by-step explanation:

34 / 100 = 0.34

0.34 is the decimal form of the fraction 34 / 100.

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3 years ago

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grandymaker [24]

5/12lb of dog food in each container.

This seems like a division problem so you would take (5/4) and divide it by 3 to make 3 equal groups meaning 5/12lb would be in each container.

I hope this helps, good luck!

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3 years ago

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Sati [7]

I believe it’s a negative slope

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3 years ago

A sample of 1200 computer chips revealed that 45% of the chips fail in the first 1000 hours of their use. The company's promotio

yaroslaw [1]

Answer:

$z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08$

$p_v = P(Z$

So the p value obtained was a low value and using the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of chips that fail in the first 1000 hours of their use is not significantly less than 0.48.

Step-by-step explanation:

Data given and notation

n=1200 represent the random sample taken

$\hat p=0.45$ estimated proportion of chips that fail in the first 1000 hours of their use

$\mu_0 =0.48$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion si less then 0.48:

Null hypothesis: $p\geq 0.48$

Alternative hypothesis: $p < 0.48$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v = P(Z$

6 0

3 years ago