Question

An office supply company sells two types of fax

Answer 1

14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.

To solve this problem, we would write a system of linear equations.

• Let x represent the machine that cost $150

• Let y represent the machine that cost $225

We can proceed to write our equations now.

$x + y = 22...equation(i)\\150x + 225y = 3900...equation(ii)$

From equation 1

$x+ y = 22\\x = 22 - y...equation (iii)$

The Value of Y

put equation (iii) into (ii)

$150x + 225y =3900\\x = 22-y\\150(22-y)+225y=3900\\3300-150y+225y=3900\\3300+75y=3900\\75y=3900-3300\\75y=600\\75y/75=600/75\\y=8$

The Value of X

Since we know the number of y, we can simply substitute it into equation (i) and solve.

$x + y = 22\\x + 8 = 22\\x = 22-8\\x = 14$

From the calculations above, 14 of the machine that cost $150 was sold and 8 of the machine that cost $255 was sold.

Learn more about system of equations here;

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