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Dmitrij [34]
3 years ago
7

The area of a rectangle is 37.5 square inches. The length of the rectangle is 15 inches. What is the width of the rectangle?

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0
Here is how to find the answer for this problem.
We know that the formula for getting the area of the rectangle is A = Length x Width. Given that the area is 37.5 inches squared and the length is 15 inches, let us just plug in the values. Let w be width.
35.7 in^2 = 15 in x w
Next, we divide both sides by 15 and this is the result
w = 2.5 inches.
Therefore, the answer would be 2.5 inches.
Hope this answer helps. Thanks for posting your question.
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What is the sum of the prime factors of the number 330?
Elena L [17]

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Step-by-step explanation:

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Given here are a set of sample data: 12.0, 18.3, 29.6, 14.3, and 27.8. the sample standard deviation for this data is equal to _
disa [49]
The answer is 7.9306

Using the formula in the attached:
Where: xi = sample value; μ = sample mean; n = sample size

1.) Calculate the mean first:
μ = 12.0 + 18.3 + 29.6 + 14.3 + 27.8 / 5
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μ = 20.4

2.) Using the mean, calculate (xi - μ)² for each value:
(12.0 - 20.4)² = 70.56
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3.) Sum the squared differences and divide by n - 1.
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3 0
3 years ago
A raft travels down river at a rate of 6 miles per hour. The total distance d in miles that the raft travels is equal to the rat
Fudgin [204]

Answer:

d=6h

Step-by-step explanation:

Speed of the raft= 6 miles per hour

Total distance (d) of the raft= rate × number of hours

d=r*h

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Dependent variable is the distance (d)

Equation for the situation

d=r*h

d=distance

r=rate

h=number of hours

From the question,

r=6 miles per hour

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The equation is

d=r*h

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8 0
3 years ago
Show solutions please
slega [8]

Answer:

1. Their ages are:

Steve's age = 18

Anne's age = 8

2. Their ages are:

Max's age = 17

Bert's age = 11

3. Their ages are:

Sury's age = 19

Billy's age = 9

4. Their ages are:

The man's age = 30

His son's age = 10

Step-by-step explanation:

1. We make the assumption that:

S = Steve's age

A = Anne's age

In four years, we are going to have:

S + 4 = (A + 4)2 - 2 = 2A + 8 - 2

S + 4 = 2A + 6 .................. (1)

Three years ago, we had:

S - 3 = (A - 3)3

S - 3 = 3A - 9

S = 3A - 9 + 3

S = 3A – 6 …………. (2)

Substitute S from (2) into (1) and solve for A, we have:

3A – 6 + 4 = 2A + 6

3A – 2A = 6 + 6 – 4

A = 8

Substitute A = 8 into (3), we have:

S = (3 * 8) – 6 = 24 – 6

S = 18

Therefore, we have:

Steve's age = 18

Anne's age = 8.

2. We make the assumption that:

M = Max's age

B = Bert's age

Five years ago, we had:

M - 5 = (B - 5)2

M - 5 = 2B - 10 .......................... (3)

A year from now, it will be:

(M + 1) + (B + 1) = 30

M + 1 + B + 1 = 30

M + B + 2 = 30

M = 30 – 2 – B

M = 28 – B …………………… (4)

Substitute M from (4) into (3) and solve for B, we have:

28 – B – 5 = 2B – 10

28 – 5 + 10 = 2B + B

33 = 3B

B = 33 / 3

B = 11

If we substitute B = 11 into equation (4), we will have:

M = 28 – 11

M = 17

Therefore, their ages are:

Max's age = 17

Bert's age = 11.

3. We make the assumption that:

S = Sury's age

B = Billy's age

Now, we have:

S = B + 10 ................................ (5)

Next year, it will be:

S + 1 = (B + 1)2

S + 1 = 2B + 2 .......................... (6)

Substituting S from equation (5) into equation (6) and solve for B, we will have:

B + 10 + 1 = 2B + 2

10 + 1 – 2 = 2B – B

B = 9

Substituting B = 9 into equation (5), we have:

S = 9 + 10

S = 19

Therefore, their ages are:

Sury's age = 19

Billy's age = 9.

4. We make the assumption that:

M = The man's age

S = His son's age

Therefore, now, we have:

M = 3S ................................... (7)

Five years ago, we had:

M - 5 = (S - 5)5

M - 5 = 5S - 25 ................ (8)

Substituting M = 3S from (7) into (8) and solve for S, we have:

3S - 5 = 5S – 25

3S – 5S = - 25 + 5

-2S = - 20

S = -20 / -2

S = 10

Substituting S = 10 into equation (7), we have:

M = 3 * 10 = 30

Therefore, their ages are:

The man's age = 30

His son's age = 10

3 0
3 years ago
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