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stealth61 [152]
3 years ago
8

Gragh h(t) = 400 − 39t − 157e−t/4

Mathematics
1 answer:
Paraphin [41]3 years ago
3 0
The graph of h(t) = 400 - 39t - 157e^{ \frac{t}{4} } is attached.

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<h3>What is the parabola?</h3>

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Let the quadratic function be y = ax² + bx + c.

The first step is to take common the coefficient of x². We have

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Add and subtract the half of the square the coefficient of x,

\rm y = a \left (x^2 + \dfrac{b}{a}x + \dfrac{b^2}{4a^2} \right) - a \times \dfrac{b^2}{4a^2} + c

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brainly.com/question/8495504

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