The complete questions is:
The ice cream shop needs 5 pounds of strawberries for every gallon of strawberry ice cream. the shop chooses to produce 4 gallons of chocolate ice cream. how many pounds of strawberries should the shop purchase?
Pounds of strawberry ice cream needed to be bought by the shop exists 20 pounds.
<h3>How many gallons of strawberry ice cream can the shop efficiently produce?</h3>
The ice cream shop requires 5 pounds of strawberries for every gallon of strawberry ice cream and the shop chooses to make 4 gallons of ice cream,
Quantity of chocolate ice cream created in the shop = 4 gallons
Quantity of strawberries needed for each gallon of ice cream = 5 pounds
Pounds of strawberries needed to be bought by the shop = Quantity of chocolate ice cream created by the shop 
Quantity of strawberries needed for each gallon of ice cream
= 20 pounds.
Pounds of strawberries needed to be bought by the shop exists 20 pounds.
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Answer: I think it’s A the cylinder
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
Answer:
x < 
Step-by-step explanation:
Given
x - 10 < 6 - 5x ( add 5x to both sides )
6x - 10 < 6 ( add 10 to both sides )
6x < 16 ( divide both sides by 6 )
x < 
, that is
x <
Answer:
a) 0.32
b) 0.68
c) office or den
Step-by-step explanation:
Locations Probabilities
Adult bedroom 0.03
Child bedroom 0.15
Other bedroom 0.14
Office or den 0.40
Other rooms 0.28
a)
P(PC in bedroom)= P(PC in adult bedroom)+ P(PC in child bedroom)+ P(PC in other bedroom)
P(PC in bedroom)= 0.03+0.15+ 0.14
P(PC in bedroom)= 0.32.
Thus, the probability that a PC is in a bedroom is 0.32.
b)
P(PC is not in bedroom)= P(PC in Office or den)+ P(PC in Other rooms)
P(PC is not in bedroom)= 0.40+0.28
P(PC is not in bedroom)= 0.68.
Thus, the probability that a PC is not in a bedroom is 0.68.
c)
When a household is selected at random from households with a PC we would expect to find a PC in a room which has a greater probability of having PC.
The greater probability of room having a PC is of Office or den room with probability 0.40. So, when a household is selected at random from households with a PC we would expect to find a PC in a Office or den room.
