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4 years ago

14

Melinda rents paddle boats down at the pier. She uses 5.5 feet of nylon rope to tie off each boat. She started with 80 feet of r

ope. After securing all the boats, she was left with more than 3 feet of rope. How many boats did Melinda tie off?

1 answer:

forsale [732]4 years ago

7 0

I think you would divide 5.5 by 80

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Simplify the question

s344n2d4d5 [400]

Answer:

=−4√2

I got this when simplified.

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3 years ago

write the equation of a line that is perpendicular to the given kine and that passes through the given point. -x+5y=14;(-5, -2)

Inga [223]

X + 5y = 14
5y = -x + 14
y = -1/5x + 14/5.....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular slope will be 5. See how I flipped -1/5 making it -5/1...and then changed the sign, making it 5.

y = mx + b
slope(m) = 5
(-5,-2)....x = -5 and y = -2
now we sub and find b, the y int
-2 = 5(-5) + b
-2 = -25 + b
-2 + 25 = b
23 = b

so ur perpendicular equation is : y = 5x + 23 <==

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3 years ago

"(b) use part (a) to find a power series for f(x) = 1 (4 + x)3 ."

Firdavs [7]

Assuming

$f(x)=\dfrac1{(4+x)^3}$

Recall that for $|x|$ ,

$\displaystyle\sum_{n\ge0}x^n=\frac1{1-x}$

Denote the above by $s(x)$ . Then

$s'(x)=\displaystyle\sum_{n\ge1}nx^{n-1}=\frac1{(1-x)^2}$
$s''(x)=\displaystyle\sum_{n\ge2}n(n-1)x^{n-2}=\frac2{(1-x)^3}$

Now,

$\dfrac1{(4+x)^3}=\dfrac1{4^3}\dfrac1{\left(1-\left(-\frac x4\right)\right)^3}=\dfrac1{2^7}\dfrac2{\left(1-\left(-\frac x4\right)\right)^3}$

which means we have

$f(x)=\dfrac1{2^7}s''(x)=\dfrac1{128}\displaystyle\sum_{n\ge2}n(n-1)\left(-\frac x4\right)^{n-2}$

which is valid for $\left|-\dfrac x4\right|$ , or $|x|$ .

4 0

3 years ago

What are the roots of the polynomial equation? x2+6x−72=0

Fantom [35]

⇒Δ=6^2+4*72= 36+288=324
V324=18

x1= ( -6+18)/2=6
x2= (-6-18)/2=-24/2=-12

⇒ x1= 6
x2= - 12

8 0

4 years ago

If all the possible random samples with n = 36 scores are selected from a normal population with µ = 50 and σ = 18, and the mean

ozzi

Answer:

Expected Value of M is 50 and the Standard Error of M is 3

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation, also called standard error $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

µ = 50 and σ = 18

For the sample

Mean 50 and standard error $s = \frac{18}{\sqrt{36}} = 3$ .

The answer is:

Expected Value of M is 50 and the Standard Error of M is 3

7 0

3 years ago