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Salsk061 [2.6K]
3 years ago
13

How do you round 8.656 to the nearest tenth

Mathematics
2 answers:
MrRissso [65]3 years ago
5 0
When you are rounding to the nearest tenth, you only look at the number right to the tenths which in this case is 5, so you round up the 6 to a 7, which will be. 

8.7
solmaris [256]3 years ago
5 0
You have 8.656 so just round 656 which will give you seven Then make the 700 a 7 for short and then stick it on to 8 which will give you 8.7
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Determine the measure of each segment then indicate whether the statements are true or false
kupik [55]

Answer:

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

  • A(-4, 4)
  • B(2, 5)

Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

  • J(2, 2)
  • K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

  • G(-5, -2)
  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

d_{JK}=5

d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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3 years ago
A giant bamboo plant grew an average of 18 centimeters per year the botanist started measuring the plant when it was 5 centimete
Yanka [14]
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4 0
4 years ago
What is the diffrence between 6 thirty-sixes and 4 thirty-sixes.?
Lilit [14]
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3 years ago
Prove: If n is a positiveinteger and n2 is<br> divisible by 3, then n is divisible by3.
notka56 [123]

Answer:

If n^2 is divisible by 3, the n is also divisible by 3.

Step-by-step explanation:

We will prove this with the help of contrapositive that is we prove that if n is not divisible by 3, then, n^2 is not divisible by 3.

Let n not be divisible by 3. Then \frac{n}{3} can be written in the form of fraction \frac{x}{y}, where x and y are co-prime to each other or in other words the fraction is in lowest form.

Now, squaring

\frac{n^2}{9} = \frac{x^2}{y^2}

Thus,

n^2 = \frac{9x^2}{y^2}

\frac{n^2}{3} = \frac{3x^2}{y^2}

It can be clearly seen that the fraction \frac{3x^2}{y^2} is in lowest form.

Hence, n^2 is not divisible by 3.

Thus, by contrapositivity if n^2 is divisible by 3, the n is also divisible by 3.

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4 years ago
Iris made bracelets with string and beads. She used x centimeters of string to make 7 bracelets. She used 17.8 centimeters of st
iren [92.7K]

Answer:

124.6 centimeters

Step-by-step explanation:

7(17.8) = x

Simplify:

x = 124.6

3 0
3 years ago
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