12.8-12.4=0.4
0.4 divide by 12.4 = 0.0322
0.0322 x 100 = 3.22%
Answer:
m(∠C) = 18°
Step-by-step explanation:
From the picture attached,
m(arc BD) = 20°
m(arc DE) = 104°
Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.
m(∠C) = ![\frac{1}{2}[\text{arc(EA)}-\text{arc(BD)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Ctext%7Barc%28EA%29%7D-%5Ctext%7Barc%28BD%29%7D%5D)
Since, AB is a diameter,
m(arc BD) + m(arc DE) + m(arc EA) = 180°
20° + 104° + m(arc EA) = 180°
124° + m(arc EA) = 180°
m(arc EA) = 56°
Therefore, m(∠C) = 
m(∠C) = 18°
A polygon cannot have curved sides. Examples of polygons include a triangle, square, rectangle, or any unnamed shape that is closed in, and has straight sides. ... A quadrilateral is a special kind of polygon that has exactly four sides that are all line segments.

Louise wants to factorize completely the given polynomial 
Grouping first, second terms together and third, fourth terms together
= 
Taking
common from first and second terms of the given expression and taking 5 common from the third and fourth terms.
=
Taking (x+3) common from the given expression,
=
is the completely factored form.
Answer:
1. x2 - 9 > 0
x^2-3^2>0
(x+3)(x-3)>0
(x+3)>0 and (x-3)>0
x>-3 and x>3
2. x2 - 8x + 12 > 0
x^2 - 8x +12>0
x^2 -2x -6x +12 >0 (-8x is replaced by (-2x) + (-6x) )
x(x-2) -6(x-2) >0
(x-6)(x-2)>0
(x-6)>0 and (x-2)>0
x>6 and x>2
3. -x2 - 12x - 32 > 0
-x^2 -12x -32 >0
x^2 +12x +32 <0
x^2 +4x +8x +32<0
x(x+4) +8(x+4)<0
(x+8)(x+4)<0
(x+8)<0 and (x+4)<0
x<-8 and x<-4
4. x2 + 3x - 20 >= 3x + 5
x^2 +3x -20 >= 3x +5
x^2 +3x -20 -3x >= 3x +5 -3x
x^2 -20 >= 5
x^2 -20 +20 >= 5 +20
x^2 >=25
x^2-25 >=0
(x-5)(x+5)>=0
(x-5)>=0 and (x+5)>=0
x>=5 and x>=-5