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a.For this part just draw a triangle with sides 4,8 and 8 inches respectively.
The sides having 8 inches should make equal angle with the base side.
b.One angle is 20
The other two angles be x and y
but x=y because its an isosceles triangle
x+y+20=180
2x=160
x=80
Hope this helps.
Using the properties of alternate angles, the value of x = 8 and ∠ A = 30
<h3>What are Alternate Angles?</h3>A transversal that crosses two parallel lines produces alternate exterior angles. They form two pairs (four total angles) of alternate outside angles since they are situated "outside" the two parallel lines but on different sides of the transversal.
For the given question,
∠A=6x−18
∠B=14x+38
As, both parallel lines are intersected by a transversal,
the value of angle ∠A and ∠180 - B is same as they are alternate angles,
⇒ 6x−18 = 180 - 14x - 38
⇒ 6x + 14x = 142 + 18
⇒ 20x = 160
⇒ x = 8
∠A = 6x−18
⇒ ∠ A = 30
To learn more abut alternate angles from given link
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