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4 years ago

8

The diameters of bolts produced by a certain machine are normally distributed with a mean of 0.30 inches and a standard deviatio

n of 0.01 inches. What percentage of bolts will have a diameter greater than 0.32 inches?a. 47.72%
b. 97.72%
c. 37.45%
d. 2.28%
e. 4.56%

1 answer:

FinnZ [79.3K]4 years ago

5 0

B. 97.72% hope this helps

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441 is 63% of what number

blagie [28]

<span>Question: 441 is 63% of what number?
=> 63% = 63% / 100% = 0.63
Since 441 is the 63% let’s find the value of 37% to get the toal of 100%
Solution, follow the formula
=> 0.63x = 441 – where x will be the value of the missing 100% value.
=> x = 441 / 0.63
=> x = 700 – the 100% value that have 441 as 63%
let’s check if we have the correct answer:
=> 700 * .63 = 441 </span>

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3 years ago

A $300 suit is marked down by %20. Find the sale price

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Answer:

1499

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(Decimal: 299.8)

Step-by-step explanation: =

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3 years ago

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I'm struggling fr now, pls can you help me answer these questions using the y= mx+ c method thanks!

Phoenix [80]

Answer:

Examination of the equation shows (graph):

x = 0, y = .5

Then .5 = c gives us the value of c giving

y = m x + .5 is our equation

Using y = 0, x = -1 gives

o = -1 * m + .5

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Check:

At x = 5, y = 3

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2 years ago

Researchers have noted a decline in cognitive functioning as people age (Bartus, 1990). However, the results from other research

kolbaska11 [484]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

Yes the researcher can conclude that the supplement has a significant effect on cognitive skill

b

$d = 0.5778$

c

The result of this hypothesis test shows that there is sufficient evidence to that the supplement had significant effect.The measure of effect size is large due to the large value of Cohen's d (0.5778 > 0.30 )

Step-by-step explanation:

From the question we are told that

The sample size is n=16

The sample mean is $M = 50.2$

The standard deviation is $\sigma = 9$

The population mean is $\mu = 45$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o \mu =45$

The alternative hypothesis is $H_a \mu \ne 45$

Generally the test statistics is mathematically represented as

$z = \frac{M - \mu}{\frac{\sigma}{\sqrt{n} } }$

=> $z = \frac{50.2 - 45}{\frac{9}{\sqrt{16} } }$

=> $z = 2.31$

Generally the p-value is mathematically represented as

$p-value = 2 * P(Z > z )$

$p-value = 2 * P(Z > 2.31 )$

From the z-table

$P(Z > 2.31 ) = 0.010444$

=> $p-value = 2 * 0.010444$

=> $p-value = 0.021$

From the obtained values we see that $p-value < 0.05$

Decision Rule

Reject the null hypothesis

Conclusion

There is sufficient evidence to conclude that the supplement has a significant effect on the cognitive skill of elderly adults

Generally the Cohen's d for this study is mathematically represented as

$d = \frac{M - \mu}{\sigma }$

=> $d = \frac{50.2 -45}{9 }$

=> $d = 0.5778$

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3 years ago

What is the simplest form of (3x^1/2)(4x^2/3)

ValentinkaMS [17]

When multiplying, we add exponents.

So first get a common denominator of 6.

3/6 + 4/6 = 7/6

So the answer is 12x^(7/6)

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