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4 years ago

PLEASE HELP!! What remainder does the number (−50) leave after division by 7?

Mathematics

1 answer:

Reil [10]4 years ago

6 0

Number -50 divided by 7 leaves a remainder of 1.
-50/7 = -7.1428
-49
------
1

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At a certain store, 55 television sets were sold in April. They want to increase sells by 30% in May. How many TVs must the sale

kari74 [83]

Answer:

Step-by-step explanation:

55(1.00 + 0.30) = 71.5 so 72 sets

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3 years ago

Use mathematical

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3 years ago

a rectangular prism is 5 meters long, 17 meters wide, and 4 meters high. what is the surface area of the rectangular prism?

Mars2501 [29]

The surface area of rectangular prism is 346 square meters.

Given the figure is rectangular prism.

We know that the surface area of rectangular prism with length L, width W and height H is = 2(LW+WH+LH)

Given that the length of prism = 5 m

Width of prism = 17 m

Height of prism = 4 m

So the total surface area of the rectangular prism is given by,

= 2 [5*17 + 17*4 + 4*5]

= 2 [85 + 68 + 20]

= 2*173

= 346 square meters

Hence the surface area of rectangular prism is 346 square meters.

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brainly.com/question/24284033

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8 0

1 year ago

A rectangular rug is 12.5 feet long and 10 feet wide. The rug needs to be reduced by a factor of One-fifth to be placed near a d

vagabundo [1.1K]

Answer:

100 square ft.

Step-by-step explanation:

The initial area of the rug is 125 ft (12.5x10)

you take the area (125) and multiply it by 1/5, or 20%. you get 25.

You then subtract 25 from 125 as the question asks to reduce the carpet by one fifth

The new rug is 100 square feet

4 0

4 years ago

How can you prove that csc^2(θ)tan^2(θ)-1=tan^2(θ)

Oxana [17]

Answer:

Make use of the fact that as long as $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ :

$\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$ .

$\displaystyle \csc(\theta) = \frac{1}{\sin(\theta)}$ .

$\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ .

Step-by-step explanation:

Assume that $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ .

Make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ and $\csc(\theta) = (1) / (\sin(\theta))$ to rewrite the given expression as a combination of $\sin(\theta)$ and $\cos(\theta)$ .

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \left(\frac{1}{\sin(\theta)}\right)^{2} \, \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} - 1 \\ =\; & \frac{\sin^{2}(\theta)}{\sin^{2}(\theta)\, \cos^{2}(\theta)} - 1\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1\end{aligned}$ .

Since $\cos(\theta) \ne 0$ :

$\displaystyle 1 = \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)}$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1 \\ =\; & \frac{1}{\cos^{2}(\theta)} - \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

By the Pythagorean identity, $\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ . Rearrange this identity to obtain:

$\sin^{2}(\theta) = 1 - \cos^{2}(\theta)$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

Again, make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ to obtain the desired result:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\\ =\; & \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} \\ =\; & \tan^{2}(\theta)\end{aligned}$ .

5 0

2 years ago