Let
A-----> ![\frac{7}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B8%7D%20%20)
B-----> ![\frac{11}{10}](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%7D%7B10%7D%20%20)
C-----> ![1](https://tex.z-dn.net/?f=%201%20)
we know that
Point A-------> Multiply numerator and denominator by ![10](https://tex.z-dn.net/?f=%2010%20)
![\frac{7*10}{8*10} =\frac{70}{80}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%2A10%7D%7B8%2A10%7D%20%3D%5Cfrac%7B70%7D%7B80%7D%20%20)
Point B-------> Multiply numerator and denominator by ![8](https://tex.z-dn.net/?f=%208%20)
![\frac{11*8}{10*8} =\frac{88}{80}](https://tex.z-dn.net/?f=%20%5Cfrac%7B11%2A8%7D%7B10%2A8%7D%20%3D%5Cfrac%7B88%7D%7B80%7D%20%20)
Point C-------> Multiply numerator and denominator by ![80](https://tex.z-dn.net/?f=%2080%20)
![\frac{1*80}{1*80} =\frac{80}{80}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%2A80%7D%7B1%2A80%7D%20%3D%5Cfrac%7B80%7D%7B80%7D%20%20)
Find the distance Point A to Point C
![\frac{80}{80} -\frac{70}{80} =\frac{10}{80}](https://tex.z-dn.net/?f=%20%5Cfrac%7B80%7D%7B80%7D%20-%5Cfrac%7B70%7D%7B80%7D%20%3D%5Cfrac%7B10%7D%7B80%7D%20%20)
Find the distance Point B to Point C
![\frac{88}{80} -\frac{80}{80} =\frac{8}{80}](https://tex.z-dn.net/?f=%20%5Cfrac%7B88%7D%7B80%7D%20-%5Cfrac%7B80%7D%7B80%7D%20%3D%5Cfrac%7B8%7D%7B80%7D%20%20)
therefore
![\frac{8}{80} < \frac{10}{80}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B80%7D%20%3C%20%5Cfrac%7B10%7D%7B80%7D%20%20)
Point B is closer to Point C
is closer to ![1](https://tex.z-dn.net/?f=%201%20)
the answer is
is closer to ![1](https://tex.z-dn.net/?f=%201%20)
Answer:
The answer is 4
Step-by-step explanation:
Answer:
195 rupees
Step-by-step explanation:
10kg=325 rupees
6kg=?
Cross multiplication;
=6×325/10
=1950/10
=195 rupees
Answer:
the answer for your question is b
<span>first stack = 12 blocks second stack = 12 + 3 = 15 blocks third stack = 15 - 7 = 8 12 + 15 + 8 = 35 blocks
So: D XDD
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