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Nadusha1986 [10]

3 years ago

9

Please give me the correct answer

2 answers:

Anastaziya [24]3 years ago

7 0

Answer:

6

Step-by-step explanation:

10^8 - 10^2 = 10^6

To check:

10^2 + 10^6 = 10^8

vlada-n [284]3 years ago

3 0

The exponent should be 6

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What is the equation of the axis of symmetry for the parabola y equals negative start fraction one over two end fraction left pa

Pachacha [2.7K]

For the equation,
y = 1/2(x+3)^2 -5
The vertice is (-3,-5). Therefore the axis of symmetry is X = -3.

7 0

3 years ago

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Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

Nonamiya [84]

Answer:

7

Step-by-step explanation:

Pythagorean Theorem:

25^2=24^2+x

625=576+x^2

49=x^2

x=sqrt49

x=7

Hope this helps!

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8 0

3 years ago

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Underline all the ordered pairs (x,y) that are solutions to the equation y=2x+1.

Romashka [77]

Answer:

<u>(3,7)</u> (7,3) (−1,14) <u>(0,1)</u> <u>(12,25)</u>

<u>(5,11)</u> (0,12) (1,8) (12,0) <u>(−1,−1)</u>

Step-by-step explanation:

We have the following function:

$y = 2x+1$ .

We are going to check if each ordered pair is a solution.

(3,7)

If when $x = 3, y = 7$ , it is a solution.

$y = 2x + 1 = 2(3) + 1 = 7$

This ordered pair is a solution.

(7,3)

If when $x = 7, y = 3$ , it is a solution.

$y = 2x + 1 = 2(7) + 1 = 15$

This ordered pair is not a solution.

(-1,14)

If when $x = -1, y = 14$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is not a solution.

(0,1)

If when $x = 0, y = 1$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is a solution.

(12,25)

If when $x = 12, y = 25$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is a solution.

(5,11)

If when $x = 5, y = 11$ , it is a solution.

$y = 2x + 1 = 2(5) + 1 = 11$

This ordered pair is a solution.

(0,12)

If when $x = 0, y = 12$ , it is a solution.

$y = 2x + 1 = 2(0) + 1 = 1$

This ordered pair is not a solution.

(1,8)

If when $x = 1, y = 8$ , it is a solution.

$y = 2x + 1 = 2(1) + 1 = 3$

This ordered pair is not a solution.

(12,0)

If when $x = 12, y = 0$ , it is a solution.

$y = 2x + 1 = 2(12) + 1 = 25$

This ordered pair is not a solution.

(-1,-1)

If when $x = -1, y = -1$ , it is a solution.

$y = 2x + 1 = 2(-1) + 1 = -1$

This ordered pair is a solution.

3 0

3 years ago

HELP ME PLEASEEEEEEEEEEEE!!!!!!!!!!!!!!!!!!!!<br> IM STRUGGLINGG

m_a_m_a [10]

Approaches 0 as x approaches infinity or C

7 0

3 years ago

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−4x−2y x−2y =−2 =9

fenix001 [56]

Dy\dx=-2+y/x+1 is the answer I think

7 0

3 years ago