Please give me the correct answer
2 answers:
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Find the percent of the circle
r=radius of circle
then r=1/2 of the diagonal of the square
use some pythagoran theorme
45,45,90 triangle
(r√2)/2=1/2 of a side
r√2 is one side
square it
2r²=square
area of circle is pir²
percent it is is
square/circle=
(2r²)/(pir²)=
2/pi= about
0.636
about 64% that it is in the square
r=radius of circle
then r=1/2 of the diagonal of the square
use some pythagoran theorme
45,45,90 triangle
(r√2)/2=1/2 of a side
r√2 is one side
square it
2r²=square
area of circle is pir²
percent it is is
square/circle=
(2r²)/(pir²)=
2/pi= about
0.636
about 64% that it is in the square
Answer:
Option (4). Rhombus
Step-by-step explanation:
From the figure attached,
Distance AB =
=
=
=
Distance BC =
=
=
Distance CD =
=
=
Distance AD =
=
=
Slope of AB () =
=
=
Slope of BC () =
=
If AB and BC are perpendicular then,
But it's not true.
[ = -
]
It shows that the consecutive sides of the quadrilateral are not perpendicular.
Therefore, ABCD is neither square nor a rectangle.
Slope of diagonal BD =
= Not defined (parallel to y-axis)
Slope of diagonal AC =
= 0 [parallel to x-axis]
Therefore, both the diagonals AC and BD will be perpendicular.
And the quadrilateral formed by the given points will be a rhombus.