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2 years ago

What is the equation of the line that is parallel to the given

Mathematics

1 answer:

Sati [7]2 years ago

8 0

i don't really get the part after the (-4,-6) , what did u write there

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Will report you if not answered correctly <br>will mark brainliest.

olga nikolaevna [1]

there are links so I could not put them in directly but hope my sticker not helps I tried my best

5 0

2 years ago

4(1-x) + 2x = -3( x + 1)

vlada-n [284]

Answer:

x = -7

Solution:

4(1-x) + 2x = -3( x + 1)

4(1 - x) + 2x = -3 (x + 1)

4(-x + 1) + 2x = -3 (x + 1)

-4x - 4 + 2x = -3(x + 1)

-2x + 4 = -3 (x + 1)

8 0

2 years ago

PLEASE ANSWER ASAP!!!!!! I WILL LOVE FOREVER LOL!!!

const2013 [10]

Point-slope form: y - y₁ = m(x - x₁)

(m is the slope, (x₁, y₁) is the point you are given that is on the line)

You know:

m = 5

(x₁, y₁) = (-2, -3) So substitute/plug it into the equation

y - y₁ = m(x - x₁)

y - (-3) = 5(x - (-2)) (two negative signs cancel each other out and become positive)

y + 3 = 5(x + 2) Your answer is A

5 0

2 years ago

Read 2 more answers

Trail mix sold in 1 Lb bags. Mary will buy trail mix for 15 members and each gets 2/5 pound bag. How many 1 lb bags should she b

solong [7]

Answer:

Mary should buy 6 bags

Step-by-step explanation:

To find the answer multiply $\frac{2}{5}$ by 15

$\frac{2}{5}*15=6$

So 6 Ib of trail mix will be perfect for the whole group

5 0

3 years ago

A wire is stretched from the ground to the top of an antenna tower. The wire is 15 feet long. The height of the tower is 3 feet

Mariana [72]

The distance d is 9 ft and the height is 12ft.

<h3>How to find the distance and the height?</h3>

Here we can model the situation with a right triangle, where the length of the wire is the hypotenuse.

The height is one cathetus and the distance is the other catheti.

Let's define:

h = height
d = distance.
hypotenuse = 15ft

We know that the height of the tower is 3 ft larger than the distance, then:

h = d + 3ft

Now we can use the Pythagorean theorem, it says that the sum of the squares of the cathetus is equal to the square of the hypotenuse.

Then:

$d^2 + (d + 3ft)^2 = (15ft)^2$

Now we can solve this equation for d:

$d^2 + d^2 + 6ft*d + 9ft^2 = (15ft)^2\\\\2d^2 + 6ft*d - 216 ft^2 = 0\\\\d^2 + 3ft*d - 108ft^2 = 0$

Then the solutions are:

$d = \frac{-3ft \pm \sqrt{(3ft)^2 - 4*(-108ft^2)} }{2} \\\\d = \frac{-3ft \pm 21ft }{2}$

We only take the positive solution:

d = (-3ft + 21ft)/2 = 9ft

And the height is 3 ft more than that, so:

h = 9ft + 3ft = 12ft

The distance d is 9 ft and the height is 12ft.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

8 0

2 years ago