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Yuliya22 [10]
2 years ago
7

Determine the Intercepts of the line. Y-intercept: (__,__) X-intercept: (__,__)

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
5 0

Answer:

I think the answer is 0.3 in 0.4

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Solve for x with a degree of 30 & side of 300ft
tankabanditka [31]

Answer:

x = 100√3


Step-by-step explanation:

tan(30º) = x/300

x = 300 tan(30º)

x = 300/√3

x = 100√3

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Find a ratio equivalent to 15/60
Flauer [41]

Answer:

\large\boxed{\dfrac{15}{60}=\dfrac{5}{20}=\dfrac{3}{12}=\dfrac{1}{4}}

or

\large\boxed{\dfrac{15}{60}=\dfrac{30}{120}=\dfrac{45}{180}=\dfrac{60}{240}}

Step-by-step explanation:

Divide the numerator and the denominator by the same number:

\dfrac{15}{60}\\\\=\dfrac{15:5}{60:5}=\dfrac{3}{12}\\\\=\dfrac{15:3}{60:3}=\dfrac{5}{20}\\\\=\dfrac{15:15}{60:15}=\dfrac{1}{4}\\\vdots

or

Multiply the numerator and the denominator by the same number:

\dfrac{15}{60}\\\\=\dfrac{15\cdot2}{60\cdot2}=\dfrac{30}{120}\\\\=\dfrac{15\cdot3}{60\cdot3}=\dfrac{45}{180}\\\\=\dfrac{15\cdot4}{60\cdot4}=\dfrac{60}{240}\\\vdots

7 0
2 years ago
Read 2 more answers
HELP WITH THIS QUESTION PLEASE!!
svetlana [45]

m<PQS = m<SQR

4y - 10 = 2y + 10

2y = 20

y = 10

m<PQR = m<PQS + m<SQR

= 4y - 10 + 2y + 10

= 6y

= 6•10

= 60

3 0
3 years ago
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