Solve the problem.
1 answer:
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Answer:
Confidence Interval: (21596,46428)
Step-by-step explanation:
We are given the following data set:
10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929
Formula:
where are data points,
is the mean and n is the number of observations.
Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821
Confidence interval:
Putting the values, we get,
Use the attached formula.
exp = [log (total / principal) / n*years]
where "n" is compounding periods per year
exp = [log (7,194.66 / 2,978.41) / (365*21)
exp = log ( <span> <span> <span> 2.4156042989 </span> </span> </span> ) / 7,665
exp = log ( <span> <span> 2.4156042989 </span> </span> ) / 7,665
exp = 0.38302579382 / 7,665
exp = <span> <span> <span> 0.00004997074935681670 </span> </span> </span>
rate = (10^exp -1)* n
rate = (10^<span>0.00004997074935681670 -1) * n
</span>rate = <span><span>(1.0001150685 </span> -1) * 365
</span>rate = <span>(.0001150685) * 365</span>
rate = <span> <span> <span> 0.0420000025 </span> </span> </span>
rate = <span>4.20000025 %
rate = 4.2 %
Yes, it's just that easy. LOL
</span>
exp = [log (total / principal) / n*years]
where "n" is compounding periods per year
exp = [log (7,194.66 / 2,978.41) / (365*21)
exp = log ( <span> <span> <span> 2.4156042989 </span> </span> </span> ) / 7,665
exp = log ( <span> <span> 2.4156042989 </span> </span> ) / 7,665
exp = 0.38302579382 / 7,665
exp = <span> <span> <span> 0.00004997074935681670 </span> </span> </span>
rate = (10^exp -1)* n
rate = (10^<span>0.00004997074935681670 -1) * n
</span>rate = <span><span>(1.0001150685 </span> -1) * 365
</span>rate = <span>(.0001150685) * 365</span>
rate = <span> <span> <span> 0.0420000025 </span> </span> </span>
rate = <span>4.20000025 %
rate = 4.2 %
Yes, it's just that easy. LOL
</span>