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qwelly [4]
3 years ago
9

Find the number of real number solutions for the equation.x2 − 2x + 9 = 0

Mathematics
1 answer:
Talja [164]3 years ago
4 0
Hi there!

We can use the discriminant of the quadratic formula to find the number of real solutions to this (or any other quadratic) equation.

The discriminant can be found by plugging in the data from the equation into the following formula:
d = {b}^{2} - 4ac \\ with \: y \: = a {x}^{2} + bx + c

When we fill in the data from the question we get
d = ( - 2) {}^{2} - 4 \times 1 \times 9 = 4 - 36 = - 32

Since d < 0 the equation has zero real solutions.
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Let m Z1=(3x)º, m 22=(5x-7)", m 23=(4x+15), and m ZAFD=128º. Find m44 and m ZBFD.​
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Answer:

m<4 = 52°

m<BFD = 98°

Step-by-step explanation:

m<1 = (3x)°

m<2 = (5x - 7)°

m<3 = (4x + 15)°

m<AFD = 128°

✔️Find m<4:

m<4 = 180° - m<AFD (angles on a straight line)

Substitute

m<4 = 180° - 128°

m<4 = 52°

✔️m<BFD = m<2 + m<3

Substitute

m<BFD = (5x - 7)° + (4x + 15)°

We need to find the value of x.

Create an equation to find x.

m<1 + m<2 + m<3 = m<AFD (angle addition postulate)

Substitute

3x + 5x - 7 + 4x + 15 = 128°

Add like terms and solve for x

12x + 8 = 128

12x + 8 - 8 = 128 - 8

12x = 120

12x/12 = 120/12

x = 10

m<BFD = (5x - 7)° + (4x + 15)°

Plug in the value of x

m<BFD = 5(10) - 7 + 4(10) + 15

m<BFD = 50 - 7 + 40 + 15

m<BFD = 98°

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