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qwelly [4]
3 years ago
9

Find the number of real number solutions for the equation.x2 − 2x + 9 = 0

Mathematics
1 answer:
Talja [164]3 years ago
4 0
Hi there!

We can use the discriminant of the quadratic formula to find the number of real solutions to this (or any other quadratic) equation.

The discriminant can be found by plugging in the data from the equation into the following formula:
d = {b}^{2} - 4ac \\ with \: y \: = a {x}^{2} + bx + c

When we fill in the data from the question we get
d = ( - 2) {}^{2} - 4 \times 1 \times 9 = 4 - 36 = - 32

Since d < 0 the equation has zero real solutions.
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The slope of the line passing through points A and B is

slope = (<em>b</em> ² - <em>a</em> ²) / (<em>b</em> - <em>a</em>) = ((<em>b</em> - <em>a</em>) (<em>b</em> + <em>a</em>)) / (<em>b</em> - <em>a</em>) = <em>b</em> + <em>a</em>

Since this line passes through (0, 3), its equation would be

<em>y</em> - 3 = (<em>b</em> + <em>a</em>) (<em>x</em> - 0)   ==>   <em>y</em> = (<em>b</em> + <em>a</em>) <em>x</em> + 3

It also passes through (-3/2, 0), so that

<em>y</em> - 0 = (<em>b</em> + <em>a</em>) (<em>x</em> + 3/2)   ==>   <em>y</em> = (<em>b</em> + <em>a</em>) <em>x</em> + 3/2 (<em>b</em> + <em>a</em>)

If these equations describe the same line, then they must have the same slope and <em>y</em>-intercept, so that

3 = 3/2 (<em>b</em> + <em>a</em>)   ==>   <u><em>a</em></u><u> + </u><u><em>b</em></u><u> = 2</u>

It also passes through (<em>a</em>, <em>a</em> ²), so that

<em>a</em> ² = (<em>b</em> + <em>a</em>) <em>a</em> + 3   ==>   <em>a</em> ² = <em>ab</em> + <em>a</em> ² + 3   ==>   <u><em>ab</em></u><u> = -3</u>

Solving for <em>b</em> in the first underlined equation, we get

<em>b</em> = 2 - <em>a</em>

Substituting into the second equation and solving for <em>a</em> gives

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==>   <em>b</em> = -1   or   <em>b</em> = 3

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