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irina1246 [14]
3 years ago
12

Use the digits 1-7 to create a seven-digit number that can be rounded to 6,300,000

Mathematics
1 answer:
g100num [7]3 years ago
3 0
<span>In order to find a number that can be rounded to 6,300,000, we need to ensure that the number to the right of the 3 (in the ten thousands place) is a number less than or equal to 4. Any number to the right of the ten thousands place would not matter what it is as long as the rounding would keep the ten thousands place at 4 or less. A number that would work is 6,342,517.</span>
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Need answer please!!!!!!!
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Answer:

Step-by-step explanation:

A=P(1+r/n)^nt

A=56057(1+((0.095)/4))^(4)2.5

A=$138922.0053

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2 years ago
What are strategies to find out what 3,208x4 is? PLEASE say it quick!
katrin2010 [14]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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A tutor kept track of how many students she had helped every week for a year. The range of the number of tutored students was 10
Lemur [1.5K]

Answer:

The difference between the smallest and largest values in the tutored students’ data was 10 students.

Step-by-step explanation:

We are given that a tutor kept track of how many students she had helped every week for a year. The range of the number of tutored students was 10 students.

As we know that the range tells us the difference between the highest and the lowest value in our data set.

In this question, it is stated that a tutor helps a certain number of students every week in a year. So, there must be a week in which she helps the maximum number of students and there must be a week in which she helps the minimum number of students.

Range = Highest value - Lowest value

Hence, the difference between the smallest and largest values in the tutored students’ data was 10 students. This is the best interpretation of this value.

8 0
3 years ago
Item to ship 76<br> Item per case 14
Igoryamba

Answer:

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Step-by-step explanation:

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4 0
2 years ago
For each geometric sequence, write a recusive rule by finding the commom ratio by calculating the ration of consecutive terms. W
Inessa05 [86]

Answer:

a_n=2.(3)^{n-1}

Step-by-step explanation:

Given sequence is:

2,6,18,54,162

So the common ratio can be found by dividing the second term by first term:

r = 6/2 = 3

The standard formula for geometric sequence is:

a_n=a_1r^{n-1}

Putting the value of r

a_n=2.(3)^{n-1}

So,

a_1=2.(3)^{1-1} => 2.3^0 = 2*1 = 2\\a_2=2.(3)^{2-1} => 2.3^1 = 2*3 = 6\\a_3=2.(3)^{3-1} => 2.3^2 = 2*9 = 18\\a_4=2.(3)^{4-1} => 2.3^3 = 2*27 = 54\\a_5=2.(3)^{5-1} => 2.3^4 = 2*81 = 162

3 0
3 years ago
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