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irina1246 [14]
3 years ago
12

Use the digits 1-7 to create a seven-digit number that can be rounded to 6,300,000

Mathematics
1 answer:
g100num [7]3 years ago
3 0
<span>In order to find a number that can be rounded to 6,300,000, we need to ensure that the number to the right of the 3 (in the ten thousands place) is a number less than or equal to 4. Any number to the right of the ten thousands place would not matter what it is as long as the rounding would keep the ten thousands place at 4 or less. A number that would work is 6,342,517.</span>
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saul85 [17]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
If I start with 3 and count by 4's until I reach 99, I get 3, 7, 11, …, 99, where 3 is the first number, 7 is the second number,
Helga [31]

Answer:

Given variables:

a=3

d=4

Tn=99

N=?

Using the formula

Tn=a+(n-1)d

99=3+(n-1)4

96=4(n-1)

24=n-1

25=n

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7 0
2 years ago
PLEASE HELP!! BRAINLIEST ANSWER AND FASTEST ANSWER GETS TON OF FREE POINTS...MATH WHIZZES, HELP ME OUT. FORGOT HOW TO DO THIS.
Julli [10]
Inscribed angles equal half of their arc length. So <D+ <B = 180
substitute: x+24+x+10 = 180 
solve: 2x + 34 = 180
2x= 146
x= 73
NOw find the measure of angle A:
<a = x + 15
<a = 73 + 15
<a = 88
 Now to find <C
<C = 180- 88
<C = 92
Hope this helps!
5 0
3 years ago
Find the value of x. <br> m27 = 2x + 18 and 2B
Reil [10]
<h2>45</h2><h2>___________________________________</h2>

8 0
3 years ago
Chuck's birthday is 2 days before Linus's.
Nat2105 [25]

Answer:

march 9

Step-by-step explanation:

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=9

I think that's the answer

6 0
1 year ago
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