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Naddik [55]
3 years ago
14

Which number is itra

Mathematics
2 answers:
True [87]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Its irrational

notka56 [123]3 years ago
4 0

Answer:

b

Step-by-step explanation:

a = 8/5 ∈ Q

c = 12 ∈ N

d = 1/2 ∈ Q

b ∈ I

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What is the slope of a line that is perpendicular to the line y = x + 4? The slope of the line is ______?
serg [7]
Slopes of perpendicular lines are opposite reciprocals of each other. The slope of the given equation (which is in slope-intercept form) is 1, the invisible coefficient of x. The opposite reciprocal of 1 is -1, thus the slope of a line perpendicular to the line y = x + 4 is -1.

Hope this helps.
8 0
3 years ago
A grocery store’s receipts show that Sunday customer purchases have a skewed distribution with a mean of 27$ and a standard devi
34kurt

Answer:

(a) The probability that the store’s revenues were at least $9,000 is 0.0233.

(b) The revenue of the store on the worst 1% of such days is $7,631.57.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{X}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

\sigma_{X}=\sqrt{n}\sigma

It is provided that:

\mu=\$27\\\sigma=\$18\\n=310

As the sample size is quite large, i.e. <em>n</em> = 310 > 30, the central limit theorem can be applied to approximate the sampling distribution of the store’s revenues for Sundays by a normal distribution.

(a)

Compute the probability that the store’s revenues were at least $9,000 as follows:

P(S\geq 9000)=P(\frac{S-\mu_{X}}{\sigma_{X}}\geq \frac{9000-(27\times310)}{\sqrt{310}\times 18})\\\\=P(Z\geq 1.99)\\\\=1-P(Z

Thus, the probability that the store’s revenues were at least $9,000 is 0.0233.

(b)

Let <em>s</em> denote the revenue of the store on the worst 1% of such days.

Then, P (S < s) = 0.01.

The corresponding <em>z-</em>value is, -2.33.

Compute the value of <em>s</em> as follows:

z=\frac{s-\mu_{X}}{\sigma_{X}}\\\\-2.33=\frac{s-8370}{316.923}\\\\s=8370-(2.33\times 316.923)\\\\s=7631.56941\\\\s\approx \$7,631.57

Thus, the revenue of the store on the worst 1% of such days is $7,631.57.

5 0
2 years ago
A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
DerKrebs [107]

Answer:

a) The probability that this whole shipment will be​ accepted is 30%.

b) Many of the shipments with this rate of defective aspirin tablets will be rejected.

Step-by-step explanation:

We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.

We select a sample of size 48 and test for defectives.

If more than one aspirin is defective, the batch is rejected.

The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48

We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

P(X\leq1)=P(X=0)+P(X=1)\\\\\\P(0)=\binom{48}{0}(0.05)^0(0.95)^{48}=1*1*0.0853=0.0853\\\\\\P(1)=\binom{48}{1}(0.05)^1(0.95)^{47}=48*0.05*0.0897=0.2154\\\\\\P(X\eq1)=0.0853+0.2154=0.3007

8 0
3 years ago
Which one should I choose
shutvik [7]

Answer:

-32

Step-by-step explanation:

((−4)(4))(2)

=−32

8 0
3 years ago
Read 2 more answers
Write two equivalent fractions for each. 1/2 and 4/5
Butoxors [25]
An equivalent fraction for 1/2 would be 2/4. This is because you can simplify 2/4 by dividing it by 2. The final answer would be 1/2.

An equivalent fraction for 4/5 would be 8/10. It's basically the same thing. Divide them both by 2 and you'll get 4/5 since 8 divided by 2 is 4, and 10 divided by 2 is 5.

5 0
3 years ago
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