Answer:
-7y^2
Step-by-step explanation:
(0.01)^(-1/2) = (1/0.01)^(1/2) = 100^(1/2) = 10
(-343 × y^6 ÷ 1000)^(1/3) =
(-343)^(1/3) × (y^6)^(1/3) ÷ 1000^(1/3)
= -7 × y^2 ÷ 10 = -0.7y^2
10 × -0.7y^2
- 7y²
(0,01)⁻¹/² × ∛(- 343y⁶/1000) =
= -(1/100)⁻¹/² × ∛( - 7³y⁶/10³)
= - 100¹/² × 7y²/10
= -(10²)¹/² × 7y²/10
= - 10 × 7y²/10
= - 7y²
The temperature at a given altitude is
y = 36 - 3x
The temperature on the surface of the planet is the point (0,t) where t is the temperature for the given height.
y = 36 - 3*0
y = 36
So at the surface of the planet is 36 degrees C.
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Effectively it is the slope of the equation which is - 3
So ever km going up will mean a loss of 3 degrees. I think they want you to write -3
