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pochemuha
3 years ago
5

Can you find the simplest form of this math problem.​

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
8 0

Answer:

-7y^2

Step-by-step explanation:

(0.01)^(-1/2) = (1/0.01)^(1/2) = 100^(1/2) = 10

(-343 × y^6 ÷ 1000)^(1/3) =

(-343)^(1/3) × (y^6)^(1/3) ÷ 1000^(1/3)

= -7 × y^2 ÷ 10 = -0.7y^2

10 × -0.7y^2

-7y^2

Wittaler [7]3 years ago
7 0

Answer:

- 7y²

Step-by-step explanation:

(0,01)⁻¹/² × ∛(- 343y⁶/1000) =

= -(1/100)⁻¹/² × ∛( - 7³y⁶/10³)

= - 100¹/² × 7y²/10

= -(10²)¹/² × 7y²/10

= - 10 × 7y²/10

= - 7y²

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The answer is 2416.5 and i did it on paper

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The Fish and Game Department stocked a lake with fish in the following proportions: 30% catfish, 15% bass, 40% bluegill, and 15%
vagabundo [1.1K]

Answer:

1) \chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

2) p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts

The Chi-Square test of independence is used "to determine if there is a significant relationship between two nominal (categorical) variables". And is defined with the following statistic:

\chi^2 =\sum_{i=1}^n \frac{(O-E)^2}{E}

Where O rpresent the observed values and E the expected values.  

State the null and alternative hypothesis

Null hypothesis: The distribution  is 30% catfish, 15% bass, 40% bluegill, and 15% pike

Alternative hypothesis: The distribution  is NOT 30% catfish, 15% bass, 40% bluegill, and 15% pike

The observed values are given by the table given:

Catfish =112, BAss = 95, Bluegill=210, Pike=83

Calculate the expected values

In order to calculate the expected values we can use the following formula for each cell of the table

E = \% Grand total

E_{Catfish}=500*0.3=150

E_{Bass}=500*0.15=75

E_{Bluegill}=500*0.4=200

E_{Pike}=500*0.15=75

Part 1: Calculate the statistic

\chi^2 =\frac{(112-150)^2}{150}+\frac{(95-75)^2}{75}+\frac{(210-200)^2}{200}+\frac{(83-75)^2}{75}=16.313

\chi^2 =16.313

Calculate the critical value

First we need to calculate the degrees of freedom given by:

df= (categories-1)=(4-1)= 3

Since the confidence provided is 95% the significance would be \alpha=1-0.95=0.05 and we can find the critical value with the following excel code: "=CHISQ.INV(0.95,3)", and our critical value would be \chi^2_{crit}=7.815

We can calculate also the p value:

p_v =P(\chi^2_{3}>16.313)=0.000978

And we got the same decision reject the null hypothesis at 5% of significance.

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2 years ago
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Answer:

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Step-by-step explanation:

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Answer for part A: Given
Answer for part B: Angle A = Angle D (not sure why this isn't in word bank?)
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-------------------------------------------------------------

Explanations:

Part A:

AB = DE is given at the very top of the problem. So we simply say "given". We always repeat what we are given at the very start of the proof. You can see this for lines 1 through 3, which are repeating the three givens. 

---------------------

Part B:

The three givens are:
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Part C:

We're using ASA (angle side angle) because we're given two pairs of congruent angles. The side for each triangle is between the two angles. See the attached diagram for more info.

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Part D:

For any proof, you will ALWAYS have the last statement be the thing you want to prove. In this case, we want to prove BC = EF. 

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Part E:

CPCTC stands for "Corresponding Parts of Congruent Triangles are Congruent"

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