Answer:
The object will hit the ground after <u>9 seconds</u>.
Step-by-step explanation:
Given:
The height 'h' of an object varies with time 'x' as:

Now, we are asked to find the time 'x' when the height reaches ground after launch.
So, the height of the object on reaching ground will be 0 m. So, substituting 0 for 'h' and solving for 'x', we get:

Therefore, there are two values of 'x' for which height is 0. The negative value is ignored as time can't be negative.
So, the value of 'x' is 9 seconds.
Hence, the object will hit the ground after 9 seconds.