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3 years ago

I really need help pls can anyone help me I would be so grateful if you help me

Mathematics

1 answer:

Pavel [41]3 years ago

7 0

Answer:

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Step-by-step explanation:

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Please someone help me...

Savatey [412]

use $a^2-b^2=(a+b)(a-b)$

to get $(\cos^3A-\sin^3A)(\cos^3A+\sin^3A)$

then use $a^3+b^3=(a+b)(a^2+b^2-ab)$

and $a^3-b^3=(a-b)(a^2+b^2+ab)$

also, $\sin^2\theta+\cos^2\theta=1$

to get $(\cos A-\sin A)(1+\sin A\cos A)(\cos A+ \sin A)(1-\sin A\cos A)$

then again use the first identity In both pairs, i.e.

$(\cos A-\sin A)(\cos A+ \sin A) \cdot (1+\sin A\cos A)(1-\sin A\cos A)$

to get $\cos 2A (1-\sin^2A\cos^2A)$

multiply and divide by 4 to get the RHS.

because, $\sin(2A)= 2\sin A \cos A$

squaring both sides, $\sin^2 (2A)=4\sin^2A\cos^2A$

3 0

3 years ago

Read 2 more answers

What is the vertical intercept for this function?<br><br> A.(0,1)<br> B. (1,0)<br> C.(0,0)

balandron [24]

I am not that sure but I am guessing it’s B.

8 0

3 years ago

Read 2 more answers

Pls help me 20 points

horsena [70]

Answer: 36

Step-by-step explanation:

-3 to the power of -2 is 9

2 to the power of 1 is 4

when you multiply that u get 36

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3 years ago

Right a word phrase for 10x 7z

sweet-ann [11.9K]

Sum of the product of 10 and x and the product of 7 and z.

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3 years ago

Zarrin [17]

iwiiwieie cud dbdgehe their djrheuurororurorytown is yeto ur

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3 years ago