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nlexa [21]
3 years ago
10

15) PLEASE HELP!!!! 10 POINTS + BRAINLIEST!!!

Mathematics
1 answer:
o-na [289]3 years ago
6 0
Multiply, and Divide

2/ 2 - 15i

2(2 + 15i)/ (2 - 15i) * 2 + 15i

= ( 4 + 30i)/ (4 + 225)

=  (4 + 30i )/ 229


Hence; 2/ 2 - 15i 
 =  4/ 229 + 30i/ 229


Therefore, Letter Choice  (D); is your answer 4/229 + 30i/229






Hope that helps!!!!
You might be interested in
Please help me with this ​
Zina [86]

Answer:

1.Triangle is heavier than a square.

2.Circle is lighter than the triangle and square.

3.3 squares won't be balanced between one triangle.

Step-by-step explanation:

Imagine Triangle is 10 and Square is 3

Triangle is heavier.

Imagine Circle is 1

3+3+3=9 also 3 squares

3 squares + 1 circle = 10

as one circle equals 1.

3 0
3 years ago
For all of the Following use the function LaTeX: P\left(x\right)\:=\:\left(x+3\right)^2+2 . My original vertex is
PolarNik [594]

Answer:

A) Q(x) = (x + 3)² + 5, and the vertex is (-3, 5)

B) R(x) = (x - 3)² + 2, and the vertex is (3, 2)

C) S(x) = (x - 1)² - 5, and the vertex is (1, -5)

Step-by-step explanation:

The given function is P(x) = (x + 3)² + 2

The given function is a parabolic function in vertex form, f(x) = a·(x - h)² + k, and vertex, (h, k)

By comparison, the vertex of the function P(x) = (x + 3)² + 2 is (-3, 2)

A) A function f(x) translated α units UP gives

f(x) (translated α units UP) → f(x) + α

A translation of the function 3 units UP is given by adding 3 to the given function as follows;

Q(x) = P(x) + 3

∴ Q(x) = (x + 3)² + 2 + 3 = (x + 3)² + 5

Q(x) = (x + 3)² + 5, and the vertex by comparison to f(x) = a·(x - h)² + k, and vertex, (h, k) is (-3, 5)

B) A function f(x) translated <em>b</em> units RIGHT gives;

f(x) translated <em>b</em> units right → f(x - b)

∴ P(x) = (x + 3)² + 2 translated 6 units RIGHT gives;

P(x) = (x + 3)² + 2 (translated 6 units RIGHT) → R(x) = (x + 3 - 6)² + 2 = (x - 3)² + 2

R(x) = (x - 3)² + 2, and the vertex by comparison is (3, 2)

C) A function translated α units DOWN and <em>b</em> units RIGHT is given as follows;

f(x) \ translated \ by\  \dbinom{b}{a} \rightarrow f(x - b) - a

Therefore, the given function, P(x) = (x + 3)² + 2, translated 7 units DOWN and 4 units RIGHT gives;

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow P(x - 4) - 7 = S(x)

S(x) = P(x - 4) - 7 = (x + 3 - 4)² + 2 - 7 = (x - 1)² - 5

P(x) = (x + 3)^2 + 5 \ translated \ by\  \dbinom{4}{-7} \rightarrow (x - 1)^2 - 5= S(x)

S(x) = (x - 1)² - 5, and the vertex by comparison is (1, -5)

7 0
3 years ago
Expanding Expressions: Expand the following expressions.
Kryger [21]

Answer:

1) \:  \:  \:  \:  \: 5(r + 2) \\ \:  \:  \:  \:  \:  \:  \:  \:  5r + 10 \\  \\ 2) \:  \:  \:  \:  \: 6b(b - 2a) \\  \:  \:  \:  \:  \:  \:  {6b}^{2}  - 12ab \\  \\ 3) \:  \:  \:  \:  \: 8cd(c - 2 + 40) \\  \:  \:   {8c}^{2}d - 16cd + 320cd \\   {8c}^{2}d - 304cd

8 0
3 years ago
Read 2 more answers
Whats the equivelent of (-1/4-1/2)/(-4/7)
Debora [2.8K]
(-1/4-1/2)/(-4/7)
= (-1/4-2/4)* (-7/4) (common denominator is 4)
= (-3/4)* (-7/4)
= 21/16
= 1 5/6

The final answer is 1 5/6~
5 0
4 years ago
Suppose that the functions p and q are defined as follows.
Brut [27]
<h2>Answer:</h2>

Answer:

(r o q)(-1) = 20

(q o r)(-1) = -11

Step-by-step explanation:

Given

q(x) = -2x + 1q(x)=−2x+1

r(x) = 2x^2 + 2r(x)=2x2+2

Solving (a): (r o q)(-1)

In function:

(r o q)(x) = r(q(x))

So, first we calculate q(-1)

q(x) = -2x + 1q(x)=−2x+1

q(-1) = -2(-1) + 1q(−1)=−2(−1)+1

q(-1) = 2 + 1q(−1)=2+1

q(-1) = 3q(−1)=3

Next, we calculate r(q(-1))

Substitute 3 for q(-1)in r(q(-1))

r(q(-1)) = r(3)

This gives:

r(x) = 2x^2 + 2r(x)=2x2+2

r(3) = 2(3)^2 + 2r(3)=2(3)2+2

r(-1) = 2*9 + 2r(−1)=2∗9+2

r(-1) = 20r(−1)=20

Hence:

(r o q)(-1) = 20

Solving (b): (q o r)(-1)

So, first we calculate r(-1)

r(x) = 2x^2 + 2r(x)=2x2+2

r(-1) = 2(-1)^2 + 2r(−1)=2(−1)2+2

r(-1) = 2*1 + 2r(−1)=2∗1+2

\begin{gathered}r(-1) = 6\\\end{gathered}r(−1)=6

Next, we calculate r(q(-1))

Substitute 6 for r(-1)in q(r(-1))

q(r(-1)) = q(6)

q(x) = -2x + 1q(x)=−2x+1

q(6) = -2(6) + 1q(6)=−2(6)+1

q(6) =- 12 + 1q(6)=−12+1

q(6) = -11q(6)=−11

Hence:

(q o r)(-1) = -11

8 0
3 years ago
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