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3 years ago

Can you help me with 4×+6=38

2 answers:

7 0

The aim here is to get all of the terms involving x on one side of the equation and then to get x by itself.

We can start by subtracting 6 from both sides.

This gives:

4x = 32

We can then divide both sides by 4 to get x by itself:

x = 32/4 = 8

expeople1 [14]3 years ago

3 0

4x+6=38
4 x 8=32
32+6=38
X=8

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Find the mean, median mode and range of: 75, 80, 60, 90, 85, 80, -7, 90, 70, 65

yaroslaw [1]

Answer:

Mean: 68.8.

Median: 77.5

Mode: 80, 90

Step-by-step explanation:

-7 + 60 + 65 + 70 + 75 + 80 + 80 + 85 + 90 + 90 = 688. Then divide by 10 because there are 10 numbers.

-7 + 60 + 65 + 70 + 75 + 80 + 80 + 85 + 90 + 90

(75, 80) are the middle numbers, so add them both, then divide by 2.

80, 90 appear more than the other numbers.

Range is highest - lowest. 90 - (-7) = 97, or it could be 83. I don't know.

4 0

3 years ago

Read 2 more answers

A 10.0 kg and a 2.0 kg cart approach each other on a horizontal frictionless air track. Their

Flura [38]

the final speed in m/s of the 10.0 kg is 2.53 m/s .

Step-by-step explanation:

Here we have , A 10.0 kg and a 2.0 kg cart approach each other on a horizontal friction less air track. Their total kinetic energy before collision is 96 ). Assume their collision is elastic. We need to find What is the final speed in m/s of the 10.0 kg mass if that of the 2.0 kg mass is 8.0 m/s . Let's find out:

We know that in an elastic collision :

⇒ Total kinetic energy before collision = Total kinetic energy after collision

⇒ $96 = \frac{1}{2}M_1(v_1)^2 + \frac{1}{2}M_2(v_2)^2$

⇒ $96 = \frac{1}{2}(10)(v_1)^2 + \frac{1}{2}(2)(8)^2$

⇒ $96=5(v_1)^2 + 64$

⇒ $5(v_1)^2 =32$

⇒ $(v_1)^2 =6.4$

⇒ $v_1 =2.53 m/s$

Therefore , the final speed in m/s of the 10.0 kg is 2.53 m/s .

8 0

3 years ago

. Let X and Y be random variables of possible percent returns (0%, 10%,

bazaltina [42]

(a) The marginal distribution of X is

Pr(X = x) = ∑ Pr(X = x, Y = y)

… = 0.0625 + 0.0625 + 0.0625 + 0.0625

… = 0.25

That is, the first equality follows from the law of total probability, with the sum taken over y from {0, 5, 10, 15}. Each probability Pr(X = x, Y = y) is given in the table to be 0.0625.

Similarly, the marginal distribution of Y is

Pr(Y = y) = 0.25

(b) Yes, they're independent because

Pr(X = x, Y = y) = 0.0625,

and

Pr(X = x) Pr(Y = y) = 0.25 • 0.25 = 0.0625.

E[X] = ∑ x Pr(X = x)

… = 0.25 ∑ x

… = 0.25 (0 + 5 + 10 + 15)

… = 7.5

and you would find the same mean for Y,

E[Y] = 7.5

The variance of X is

V[X] = E[X^2] - E[X]^2

… = (∑ x^2 Pr(X = x)) - 7.5^2

… = 0.25 (∑ x^2) - 56.25

… = 0.25 (0^2 + 5^2 + 10^2 + 15^2) - 56.25

… = 31.25

and similarly,

V[Y] = 31.25

(each sum is taken with x and y from {0, 5, 10, 15})

7 0

3 years ago

10×3.26= so what is the answer for this question

max2010maxim [7]

(10)(3.26)=32.6

Your answer is in Bold.

~Good Luck~

3 0

3 years ago

Read 2 more answers

which equation in point slope form correctly represents zadas pay in dollars, y, when she works x hours?

Firlakuza [10]

ANSWER

The correct answer is A

$y-68=2(x-4)$

EXPLANATION

We were told that Zada is paid at an hourly rate of $ $12$ per hour.

The unit rate of payment represents the slope of the straight line graph that models Zada's earnings. Thus $m=12$

When she works for 4 hours she earns a total of $68 tells us that the point, $(4,68)$ lies on the model straight line.

Using the formula for the point slope form

$y-y_1=m(x-x_1)$

we obtain the equation as follows.

$y-68=2(x-4)$

3 0

3 years ago