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3 years ago

Whats the right answer?

Mathematics

2 answers:

Andrei [34K]3 years ago

7 0

The right answer is D

il63 [147K]3 years ago

3 0

in my opinion the answer is D

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8 divde by 1/6 equals 48 because<br><br>

nika2105 [10]

Proof:

$8\div\frac{1}{6}=\frac{8}{1}\div \frac{1}{6}=\frac{8}{1}\times\frac{6}{1}=\frac{8\times6}{1}=\frac{48}{1}=48 \\$

6 0

3 years ago

What is the equation of the axis of symmetry for the parabola y equals negative start fraction one over two end fraction left pa

Pachacha [2.7K]

For the equation,
y = 1/2(x+3)^2 -5
The vertice is (-3,-5). Therefore the axis of symmetry is X = -3.

7 0

3 years ago

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How do you do this problem?

Burka [1]

Let area of triangle AEC = x

Area of triangle BAC = 1/2 * 15 * 12 = 90

Area of triangle DCA = 1/2 * 15 * 6 = 45

90 = p + x and

45 = q + x Subtracting the 2 equations:-

90 - 45 = p - q

Answer p - q = 45

7 0

3 years ago

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Find the x and y intercepts of the line. Enter each answer as an ordered pair

Dmitriy789 [7]

Answer:

what to do will I show the image

6 0

2 years ago

In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p

skelet666 [1.2K]

Answer:

$\mathbf{P(X=5) =0.0888}$

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

$\mathtt{P(X=x) =(^{n}_{x} ) \ \pi^x \ (1-\pi)^{n-x}}$

$\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} ) \ \pi^x \ (1-\pi)^{n-x}}$

where;

n = 8 and π = 0.36

For x = 5

The probability $\mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} ) \ 0.36^5 \ (1-0.36)^{8-5}}$

$\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} ) \ 0.36^5 \ (0.64)^{3}}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =({8 \times 7 } ) \times \ 0.0060466 \ \times 0.262144}$

$\mathtt{P(X=5) =0.0887645}$

$\mathbf{P(X=5) =0.0888}$ to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5) $\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})$

${P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times (0.36)^0 \times (1-0.36)^8 \ ) + \dfrac{8!}{1!(7!)} \times (0.36)^1 \times (1-0.36)^7 \ +$ $\dfrac{8!}{2!(6!)} \times (0.36)^2 \times (1-0.36)^6 \ + \dfrac{8!}{3!(5!)} \times (0.36)^3 \times (1-0.36)^5 + \dfrac{8!}{4!(4!)} \times (0.36)^4 \times (1-0.36)^4 \ + \dfrac{8!}{5!(3!)} \times (0.36)^5 \times (1-0.36)^3 \ )$

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1 - P( x ≤ 5 )

P ( x ≥ 6) = 1 - 0.9707

P ( x ≥ 6) = 0.0293

4 0

3 years ago