Answer:
54
Step-by-step explanation:
Tn = an²+bn
T2 = a2²+2b
2 = 4a +2b
Multiply all through by 2
4 = 8a +4b
4b = 4-8a
T4 = a4² + 4b
20 = 16a +4b
4b = 20-16a
4-8a = 20-16a
16a -8a = 20-4
8a = 16
a = 16/8 = 2
4b = 4-8a = 4-8(2) = 4-16 = -12
b = -12/4 = -3
T6 = a6² + 6b
T6 = 2(36) + 6(-3) = 72 -18 = 54
Answer:
1_11/20 pounds, or 1.55 pounds.
Step-by-step explanation:
Since at the beginning, he had 5 1/4 pounds and used 3/5, we subtract the amount of pounds. We are then left with 93/20 pounds, which he then splits among 3 containers. Dividing by three, we then get 31/20 pounds in one aquarium, or 1 11/20 pounds in each aquarium or 1.55 pounds.
Set up a ratio comparing the sample portion to the whole portion.
x= # of all dogs likely to have chip
Sample: 8 out of 50
Whole: x out of 2,300
8/50= x/2300
cross multiply
(50*x)= (8*2300)
50x= 18400
divide both sides by 50
x= 368
ANSWER: 368 dogs in Clarkson are likely to have a microchip.
Hope this helps! :)
