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Musya8 [376]
3 years ago
14

Meg mixes 3 parts silver paint with 4 parts green paint to get a specific color. Is the ratio 5:6 equivalent to 3:4?

Mathematics
2 answers:
damaskus [11]3 years ago
7 0

Answer:

No, because the numbers in the given ratio must be multiplied by the same number.

Step-by-step explanation:

Essentially, ratio to be equal must be equal. E.g. 3:4 would be equal to 6:8 because you multiply both sides of the ratio by 2.

marysya [2.9K]3 years ago
3 0

Answer:

answer is No, because the numbers in the given ratio must be multiplied by the same number. or c

Step-by-step explanation:

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Please help ASAP THIS IS MY FINAL QUESTION!!!! 20 points!!!!
givi [52]

Answer:

y= 1/2x-3

Step-by-step explanation:

2y - x = 8

First find the slope

2y = x+8

Divide by 2

2y/2 = x/2 +8/2

y = 1/2 x +4

The slope is 1/2  ( y=mx+b where m is the slope and b is the y intercept)

When lines are parallel they have the same slope)

Using y = mx+b

y =1/2x+b

Substituting the point (4,-1) into the equation

-1 =1/2(4)+b

-1 = 2+b

-3 =b

The equation of the line is

y= 1/2x-3

4 0
2 years ago
A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and
vredina [299]

Answer:

2.35%

Step-by-step explanation:

Mean number of months (M) = 39 months

Standard deviation (S) = 10 months

According to the 68-95-99.7 rule, 95% of the data is comprised within two standard deviations of the mean (39-20 to 39+20 months), while 99.7% of the data is comprised within two standard deviations of the mean (39-30 to 39+30 months).

Therefore, the percentage of cars still in service from 59 to 69 months is:

P_{59\ to\ 69}=\frac{P_{9\ to\ 69}-P_{19\ to\ 59}}{2} \\P_{59\ to\ 69}=\frac{99.7-95}{2}\\P_{59\ to\ 69}=2.35\%

The approximate percentage of cars that remain in service between 59 and 69 months is 2.35%.

8 0
2 years ago
Can anyone help me please?
miss Akunina [59]

Answer:

  5. -18x^3y^4 +54x^2y^4

  6. 6x^2 -40x +50

Step-by-step explanation:

Use the distributive property. The factor outside parentheses multiplies each term inside parentheses.

__

<h3>5.</h3>

  (9xy)(-2x^2y^3+6xy)=(9xy)(-2x^2y^3)+(9xy)(6xy^3)\\\\=\boxed{-18x^3y^4+54x^2y^4}

__

<h3>6.</h3>

  (3x-5)(2x-10)=3x(2x-10)-5(2x-10)\\\\=6x^2-30x-10x+50=\boxed{6x^2-40x+50}

7 0
2 years ago
How to do this question
Tema [17]

Answer:

f(8) = \underline{5}

Step-by-step explanation:

We can see it on the given table of values.

6 0
3 years ago
Does anyone know the answer?
melamori03 [73]

<em>value \: of  \: x \: is \: 210 \\please \: see \: the \: attached \: picture \\ for \: full \: solution \\ hope \: it \: helps</em>

6 0
3 years ago
Read 2 more answers
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