Ask question

Ask question

All categories

3 years ago

13

How can you change linear equation in form ax+by=c to y=mx+b form and vice versa

1 answer:

OlgaM077 [116]3 years ago

3 0

You simply have to take the linear equation form (ax + by = c) and solve for y. So you get:
by = c - ax
y = c/b - ax/b

Since c/b will be a constant, you can replace it with any variable (i.e. b), and so that represents the y-intercept and a/b will also be a constant, so that can also be replaced by any variable (i.e. m), and it represents the slope.

You might be interested in

(a^3)^6 = (a^2)^x what is x?

alexgriva [62]

Answer:

9

Step-by-step explanation:

Solution

Here,

(a^3)^6=(a^2)^x

or, a^18=a^2x

or, 18=2x

or, x=18/2

x=9

8 0

3 years ago

A group of students are randomly placed in either a traditional AP Stat class or an online-only AP Stat class. Both classes take

BaLLatris [955]

Answer:

Mean or Expected Value:

μ

=

∑

x

i

n

X

x

P

(

x

)

Standard Deviation:

σ

=

√

∑

x

i

n

X

(

x

−

μ

)

2

P

(

x

)

Step-by-step explanation:

8 0

3 years ago

WILL GIVE BRAILNLIESTThe oblique pyramid has a square base. An oblique pyramid has a square base with a base edge length of 2 ce

rusak2 [61]

Answer:

6 cm^3

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Almost there .......AAAAHHhH

madreJ [45]

Answer:

12/46

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili

Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

$\lambda= 4.5$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

a) No accidents occur in one week.

$P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111$

b) 5 or more accidents occur in a week.

$P( x \geq 5) = 1-\displaystyle \sum P(x$

c) One accident occurs today.

The mean number of accidents per day is given by

$\lambda = \dfrac{4.5}{7} = 0.64$

$P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747$

5 0

3 years ago