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Doss [256]
3 years ago
15

The question is below pls help.

Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

The answer is 153.8

Step-by-step explanation:

To find the perimeter you sum all the sides. 5.9+12.3+12.3+10.9+12.3+23.2+18.2+10.9+12.3+35.5= 153.8

You might be interested in
What is the 8th term of the geometric sequence a2 = 20 and r = 5
algol [13]

Answer:

8th term of geometric sequence is 312500

Step-by-step explanation:

 Given :  a_2=20 and common ratio (r) = 5

We have to find the 8th term of the geometric sequence whose a_2=20 and common ratio (r) = 5  

Geometric sequence is a sequence of numbers in which next term is found by multiplying by a constant called the common ratio (r).

     a_n=ar^{n-1}  ......(1)

where  a_n  is nth term and a is first term.

For given sequence

a can be find using  a_2=20 and r =  5

Substitute in (1) , we get,

a_2=ar^{2-1}

\Rightarrow 20=a(5)  

\Rightarrow a=4

Thus, 8th term of the sequence denoted as  a_8

Substitute n= 8 in (1) ,  we get,

a_8=ar^{8-1} \\\\a_8=(4)r_{7} \\\\a_8=4(5)^7=4 \times 78125=312500

Thus 8th term of geometric sequence is 312500

8 0
3 years ago
5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?​
Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0
2 years ago
PLEASE HELP I GIVE BRAINLIEST
melamori03 [73]

Here is my answer. I hope this is helpful.

4 0
3 years ago
Ashleyhas$40inasavingsaccount.Theinterestrateis 10% peryearandisnotcompounded.Howmuchwillshehavein4years?
ss7ja [257]

Answer:

58.564

or $58.56

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can I have help? With this it’s due today and it’s really hard high school level
Anna007 [38]
J=1

explaination:
2 is greater than or equal to 3
4 - j(1)= 3
4 0
2 years ago
Read 2 more answers
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