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2 years ago

Pls give me the answer to 12 – 3x = -6х

Mathematics

1 answer:

Kisachek [45]2 years ago

4 0

Answer:

-4

Step-by-step explanation:

Move variables to one side and numbers on the other.

12 - 3x = -6x

+ 3x +3x

12 = -3x

/-3 /-3

-4 = x

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HELP ASAP ILL GIVE YOU 13 points

lubasha [3.4K]

Answer:

the domain and range can be found by horizontal and vertical test

Step-by-step explanation:

6.B

7.D

8.A

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1 year ago

Find the total weight of 10 chunks of cheese at 3/4 a pound

Svetllana [295]

3/4 lb × 10 chunks =
3/4 × 10 =
30/4 = 7 2/4 = 7 1/2 lbs

5 0

2 years ago

Brian says that the expression 8n + 2 is equal to 83 when n=1. Explain why Brian’s answer is incorrect?

GalinKa [24]

Answer:

8n+2 first let’s plug in n which is 1

8(1)+2=10

The answer is 10 but Brian said the expression is equal to 83. He is incorrect because 8 times 1 is 8 and then plus 2 is 10.

I hope it helps.

5 0

1 year ago

The U.S. Census Bureau announced that the median sales price in 2014 for new homes was $282,800 and the mean sales price was $34

victus00 [196]

Answer:

a) 0.9964

b) 0.3040

Step-by-step explanation:

Given data:

standard deviation = $90,000

Mean sales price =$345,800

sample mean = $370,000

Total number of sample = 100

calculate z score for [/tex](\bar x = 370000)[/tex]

$z = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{370000 - 345800}{\frac{90000}{\sqrt{100}}}$

z = 2.689

P(x<370000) = P(Z<2.689)

FROM STANDARD NORMAL DISTRIBUTION TABLE FOR Z P(Z<2.689) = 0.9964

calculate z score for (\bar x = 350000)

$z = \frac{\bar x - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{350000 - 345800}{\frac{90000}{\sqrt{100}}}$

z = 2.133

$P(350000 \leq \bar x \leq 365000) = P(0.467 \leq Z\leq 2.133) = P(Z\leq 2.133) - P(Z\leq 0.467)$

FROM NORMAL DISTRIBUTION TABLE Z VALUE FOR

$P(Z\leq 2.133) = 0.9836$

$P(Z\leq 0.467) = 0.6796$

SO, = 0.9836 - 0.6796 = 0.3040

4 0

2 years ago

Please answer both thank you

jeyben [28]

Answer:

Solution given;

male=15

female=27

1st term=5*3

2nd term=3*3*3

now

Highest common factor=3

The maximum number of groups that the teacher can make is 3.

and each team contains 5 male and 9 female.

7 0

2 years ago