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joja [24]
3 years ago
14

Where would square root 113 be located on a number line

Mathematics
1 answer:
Amanda [17]3 years ago
5 0

Answer: It's between 10 and 11

It's closer to 11 than it is to 10.

This is because \sqrt{113} \approx 10.63 after using a calculator.

You could also look at the list of perfect squares

{1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144,...}

The terms in bold are where 113 fits in between. So we can say,

100 < 113 < 121\\\\\sqrt{100} < \sqrt{113} < \sqrt{121}\\\\10 < \sqrt{113} < 11\\\\

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Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 4e2x - 3 - 5 = 0
Deffense [45]

Answer:

Value of x will be 0.1515

Step-by-step explanation:

We have given the equation 4e^{2x}-3-5=0

We have top fond the value of x using exponent and logarithmic property

So 4e^{2x}-3-5=0

4e^{2x}-8=0

4e^{2x}=8

e^{2x}=2

Taking log both side

lne^{2x}=ln2

2x=0.3010

x = 0.1515

4 0
3 years ago
Pls help I will give brainliest answer
notsponge [240]

Answer:

I think the answer is 8 rounding tho would be 10

Step-by-step explanation:

6 0
3 years ago
Use the parabola tool to graph the quadratic function y=-1? - 2.0 +8
Andreas93 [3]

Answer:

see explanation

Step-by-step explanation:

I don't have graphing facilities but can give you the vertex and 1 other point.

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = - x² - 2x + 8 ← is in standard form

with a = - 1 and b = - 2 , then

x = - \frac{-2}{-2} = - 1

Substitute x = - 1 into the equation for corresponding value of y

y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9

vertex = (- 1, 9 )

To obtain another point substitute any value for x into the equation

x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph

x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0  then (2, 0 ) is a point on the graph

3 0
3 years ago
Find two numbers whose sum is 25 and the sum of whose reciprocals is 1/6
Katen [24]

Answer:

10 and 15

Step-by-step explanation:

Let 'x' and 'y' are the numbers we need to find.

x + y = 25 (two numbers whose sum is 25)

(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)

The solutions of the this system of equations are the numbers we need to find.

x = 25 - y

1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y

6y + 6(25-y) = (25-y)y

6y + 150 - 6y = 25y - (y^2)

y^2 - 25y + 150 = 0 quadratic equation has 2 solutions

y1 = 15

y2 = 10

Thus we have :

First solution: for y = 15, x = 25 - 15 = 10

Second solution: for y = 10, x = 25 - 10 = 15

The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).

5 0
3 years ago
Find the 31st term of the sequence 12,16,20
Natali [406]

Answer:

136

Step-by-step explanation

multiply 4 by 31 and add 20

6 0
4 years ago
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