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fgiga [73]
3 years ago
5

(y4 – y3 + 2y2 + y – 1) ÷ (y3 + 1)

Mathematics
2 answers:
marta [7]3 years ago
7 0

Answer:

The correct answer is 2y^2

Step-by-step explanation:

Monica [59]3 years ago
5 0
<span>a+b) • (a2-ab+b2)
</span><span>(a+b) • (a2-ab+b2) = 
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+<span>b<span>3
ANWSER </span></span></span><span> y4 - y3 + 2y2 + y - 1 —————————————————————— (y + 1) • (y2 - y + 1)</span>
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Yupin is making fruit punch. The recipe calls for 2 ½ of guava juice. The guava juice container has 4 ¼ cups of juice in it. How
astraxan [27]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
I’m confused and don’t have an angle tool to even try to do the question
yanalaym [24]
<h3>Answer:   40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0
3 years ago
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