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3 years ago

Please help!!!!!!!!!!! ASAPPPPPPPPP

Mathematics

1 answer:

Zanzabum3 years ago

7 0

When you match the pattern of (x+y)⁴ to (a+b)ⁿ, you see that a=x, n=4. Then the first term aⁿ can be found by substituting these values for "a" and "n":

... x⁴

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How do i solve tis in need help <br> slope=2/7 y-intercept=-4

Thepotemich [5.8K]

Answer:

y=2/7x-4

Step-by-step explanation:

Write in Slope intercept form

y=mx+b

m = slope

b = y intercept

x = x intercept

y = (0,-4)

So,

y = 2/7x+(-4) substitute

y = 2/7x-4

5 0

2 years ago

I=prt for t I=105 p=700 and r=0.05

Pachacha [2.7K]

t = 3

Simple interest will be derived by multiplying the principal, the interest rate, and the term.

Interest = Principal x Rate x Term

Interest = 105
Principal = 700
Rate = 0.05
Term = ?

Based on the Simple Interest formula,

term = Interest / principal x rate
term = 105 / (700 x 0.05)
term = 105 / 35
term = 3

7 0

3 years ago

4+(−123). Write your answer as a fraction in simplest form.

Leviafan [203]

Answer:

-119

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

9 months ago

Allen traveled for 7 hours at a constant rate of 40 miles per hour. Anna traveled the same distance at a constant rate of 50 mil

TEA [102]

Here is the correct order of the step:

Identify: Anna's time is the unknown

Strategize : let x = Anna's time

Set up : 7(40) = x(50)

Solve: x = 5.6

Check: 7(40) = 5.6(50)

The first step is to determine the distance Allen travelled:

Distance = average speed x time

40 x 7 = 280 miles

The second step is to determine the time it took Anna to travel 280 miles.

Time = distance / average speed

280 / 50 = 5.6 hours

To learn more about average speed, please check: brainly.com/question/21734785

#SPJ1

3 0

1 year ago