A vector that has a magnitude of one.
There are 2 tangent lines that pass through the point

and

Explanation:
Given:

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:
![[1]](https://tex.z-dn.net/?f=%5B1%5D)
For the lines to be tangent to the curve, we must substitute the first derivative of the curve for
:



![[2]](https://tex.z-dn.net/?f=%5B2%5D)
Substitute equation [2] into equation [1]:
![[1.1]](https://tex.z-dn.net/?f=%5B1.1%5D)
Because the line must touch the curve, we may substitute 

Solve for x:




± 
±
<em> </em>

There are 2 tangent lines.

and

Answer:
xy=2
Step-by-step explanation
2x + 3y =12
First divide 2 on both sides of the equation, than divide 3 on both sides of the equation.
values that are <u>excluded from the domain</u> of a rational expression are values that make the denominator 0, since if that's so, the rational will be undefined. That happens when the denominator is zero out, let's do so

so, if ever m = 0, the denominator will become 0 and the rational becomes undefined, and whenever n = -3, the same will happen to the rational, thus those values are excluded.
Multiply each term in the parenthesis by -4
-4 • 6n-4•(-5)+3a
Calculate the product -4•6n= -24n
Multiply the numbers -4•(-5)= +20
Then put every thing together
Final Answer: -24n+20+3a