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adelina 88 [10]
3 years ago
15

Solve for x I don't know how to solve it​

Mathematics
1 answer:
mixer [17]3 years ago
8 0

Answer:

x=-12

Step-by-step explanation:

32+2x=6+x+14

2x-x=6+14-32

x=-12

ST=6

TU=-12+14=2

SU=6+2=8

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Jake monthly expenses include a $60 cable bill, a $200 car payment and $120 for car insurance. If he brings home $525 per month,
Anit [1.1K]

Answer:

he would have 145 dallors after baying his bills


Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
Find the Mean of the following set of data. (Round to the
Vikentia [17]

Answer:

2.75

Step-by-step explanation:

to get the mean all you have to is add all the numbers up then divide by how numbers there are. so 3e is what u get when u add them up then divide by 12 and u get 2.75

3 0
3 years ago
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
PLEASE ANSWER THIS QUESTION <br>Show that 4x – 7 is equivalent to 4(x - 1) – 3 when x = 3.​
Drupady [299]

Answer:

4(3) - 7 = 4(3 - 1) - 3

12 - 7 = 4(2) - 3

5 = 8 - 3

= 5

They are equivalent because when they are both simplified they have the same answer 5

7 0
3 years ago
7. Find a conversion factor between cubic meters and cubic
RUDIKE [14]

Step-by-step explanation:

We know that,

1 m = 100 cm

the conversion from m² to cm² is as follows :

(1 m)² = (100 cm)² = 10000 cm²

A conversion factor between cubic meters and cubic  centimeters is as follows :

(1 cm)³ = (100 cm)³

= 1000000 cm³

To convert m³ to cm³, multiply by 1000000.

Hence, this is the required solution.

3 0
3 years ago
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