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adelina 88 [10]
3 years ago
15

Solve for x I don't know how to solve it​

Mathematics
1 answer:
mixer [17]3 years ago
8 0

Answer:

x=-12

Step-by-step explanation:

32+2x=6+x+14

2x-x=6+14-32

x=-12

ST=6

TU=-12+14=2

SU=6+2=8

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What is a unit vector
Anna35 [415]
A vector that has a magnitude of one.
8 0
3 years ago
56. How many tangent lines to the curve <img src="https://tex.z-dn.net/?f=y%3Dx%20%2F%28x%2B1%29" id="TexFormula1" title="y=x /(
PIT_PIT [208]

There are 2 tangent lines that pass through the point

y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2

and

y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2

Explanation:

Given:

y=\frac{x}{x+1}

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:

y=m(x-1)+2 [1]

For the lines to be tangent to the curve, we must substitute the first derivative of the curve for m:

\frac{dy}{dx} =\frac{d(x)}{dx}(x+1)-x^\frac{d(x+1)}{dx} \\ \\

\frac{dy}{dx} =\frac{x+1-x}{(x+1)^2}

\frac{dy}{dx}= \frac{1}{(x+1)^2}

m=\frac{1}{(x+1)^2} [2]

Substitute equation [2] into equation [1]:

y=\frac{x-1}{(x+1)^2}+2 [1.1]

Because the line must touch the curve, we may substitute y=\frac{x}{x+1}:

\frac{x}{x+1}=\frac{x-1}{(x+1)^2}+2

Solve for x:

x(x+1)=(x-1)+2(x+1)^2

x^2+x=x-1+2x^2+4x+2

x^2+4x+1

x\frac{-4±\sqrt{4^2-4(1)(1)} }{2(1)}

x=-2 ± \sqrt{3}

x=-2 ± \sqrt{3}<em> </em>and x=-2-\sqrt{3}

There are 2 tangent lines.

y=\frac{1}{(-1+\sqrt{3)^2} } (x-1)+2

and

y=\frac{1}{(-1-\sqrt{3)^2} } (x-1)+2

8 0
2 years ago
2x+3y=12 find the missing value
Ilia_Sergeevich [38]

Answer:

xy=2

Step-by-step explanation

2x + 3y =12

First divide 2 on both sides of the equation, than divide 3 on both sides of the equation.

5 0
3 years ago
What are the excluded values? m+5/mn+3m
In-s [12.5K]

values that are <u>excluded from the domain</u> of a rational expression are values that make the denominator 0, since if that's so, the rational will be undefined.  That happens when the denominator is zero out, let's do so

\bf mn+3m=0\implies m(n+3)=0\implies \begin{cases} m=0\\ n=-3 \end{cases}

so, if ever m = 0, the denominator will become 0 and the rational becomes undefined, and whenever n = -3, the same will happen to the rational, thus those values are excluded.

7 0
3 years ago
-4(6n-5)+3a what is the solution
igor_vitrenko [27]
Multiply each term in the parenthesis by -4

-4 • 6n-4•(-5)+3a

Calculate the product -4•6n= -24n
Multiply the numbers -4•(-5)= +20
Then put every thing together
Final Answer: -24n+20+3a
7 0
3 years ago
Read 2 more answers
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