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adelina 88 [10]
3 years ago
15

Solve for x I don't know how to solve it​

Mathematics
1 answer:
mixer [17]3 years ago
8 0

Answer:

x=-12

Step-by-step explanation:

32+2x=6+x+14

2x-x=6+14-32

x=-12

ST=6

TU=-12+14=2

SU=6+2=8

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Jeff put a small box that is 12 inches long,8 inches wide, and 4 inches tall inside a box that is 20 inches,15 inches wide, and
vodka [1.7K]
The answer can be found by subtract the volume of the small box from the volume of big box.

Volume of the small box:
12*8*4= 384 inches cube

Volume of the big box:
20*15*9= 2700 inches cube

The space left:
2700 - 384 = 2316 inches cube
3 0
3 years ago
–0.4(3x – 2) + StartFraction 2 x plus 4 Over 3 EndFraction for x = 4
Nadusha1986 [10]

Answer:

0

Step-by-step explanation:

Given

- 0.4(3x - 2) + \frac{2x+4}{3} ← substitute x = 4 into the expression

= - 0.4(3(4) - 2) + \frac{2(4)+4}{3}

= - 0.4(12 - 2) + \frac{8+4}{3}

= - 0.4(10) + \frac{12}{3}

= - 4 + 4 = 0

4 0
3 years ago
Read 2 more answers
Find the distance between the points (-1,5) and (-7,3)
natima [27]

Answer:

2√10

Step-by-step explanation:

On the attached file

3 0
4 years ago
Read 2 more answers
Whats the answer for substitution x=9 y=3x-1
Blizzard [7]

Answer:

x=9, y=26. (9, 26).

Step-by-step explanation:

x=9

y=3x-1

--------

y=3(9)-1=27-1=26

8 0
3 years ago
Read 2 more answers
The numerical value of sin²5° + sin²10° + sin²15° +... sin²85° + sin²90° is equal a) 17/2 b) 19/2 c) 15/2 d) 13/2​
Vikki [24]

Answer: b)~\Large\boxed{\frac{19}{2} }

Step-by-step explanation:

<h3>Given expression</h3>

sin²5° + sin²10° + sin²15° +... sin²85° + sin²90°

<h3>Concept:</h3>

sin²x + cos²x = 1

sin(x) = cos (90 - x)

<u />

<u>There are in total these terms:</u>

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90

<u>In total, there are 18 terms, and the first one matches with the second to the last one:</u>

5 -- 85

10 -- 80

.

.

.

40 -- 50

<u />

<u>There are 2 terms left over:</u>

sin²45 and sin²90

<h3>Convert the first half of the sine terms (sin²5 - sin²40) to the cosine terms</h3>

sin²5 = cos² (90 - 5) = cos²85

sin²10 = cos² (90 - 10) = cos²80

.

.

.

sin²40 = cos² (90 - 40) = cos²50

<h3>Simplify the 16 grouped terms </h3>

<em>i.e. sin²85 and cos²85</em>

Using the concept of sin²x + cos²x = 1

sin²85 + cos²85 = 1

sin²80 + cos²80 = 1

.

.

.

sin²50 + cos²50 = 1

Total = (16/2) × 1 = 8 × 1 = 8

<h3>Evaluate the 2 terms that are left over</h3>

sin²45 = (sin45) (sin45) = (√2 / 2) (√2 / 2) = 1/2

sin²90 = (sin90) (sin 90) = (1) (1) = 1

<h3>Add all the terms together</h3>

8+\dfrac{1}{2} +1=\Large\boxed{\frac{19}{2} }

Hope this helps!! :)

Please let me know if you have any questions

8 0
1 year ago
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