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Alex_Xolod [135]
3 years ago
13

PLS HELP MEEEEE!!!!!!!!!!!!

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
8 0

Answer: (2,1)

Step-by-step explanation:

Andreyy893 years ago
6 0

Answer:

(1,2)

Step-by-step explanation:

The solution is the point where the two lines intersect at.

In other words the point where the two lines make an x.

Hope this helps ya!!

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(06.01)The tables below show four sets of data:
Yakvenalex [24]
For it to be non-linear, the rate of change cannot be constant.  For the first table the rate is a constant 1 and the second table has a constant rate of -1.  The 3rd and 4th tables have no constant rate and thus are non-linear.

The 4th table is increasing while the 3rd table is decreasing.  

So the 3rd table, Set C, is the only non-linear negative association between x and y. 
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3 years ago
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The weight, in grams, of eight different kiwis was used to create the box plot shown above. Which of the sets of numbers below m
Basile [38]

Answer:

Step-by-step explanation:

The answer is d because 75 is the medain of the kiwi fruit

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4 years ago
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A polynomial that has 4 turning points is multiplied by another polynomial that has 9 zeros. What is the minimum degree of the n
pickupchik [31]
For a given degree of the polynomial, the number of turning points is given by n-1, where n is the degree of the polynomial. A polynomial that has x number of zeros is a polynomial of degree x. Thus the polynomial that has 9 zeros and 4 turning points, is a polynomial of degree 9.
5 0
3 years ago
Describe the transformations that will make f(x)=1/x into g(x)=−1x+5−8?
Anton [14]

Answer:

f (x) = 4

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Step-by-step explanation:

Hope this helped you.

Have a beautiful day!!

7 0
3 years ago
Use a direct proof to show that the product of two odd integers is odd.
yulyashka [42]

Answer:

The proof itself

Step-by-step explanation:

We can define the set of all even numbers as

E = \{ a \in \mathbb{Z} \setminus a = 2.k , k\in \mathbb{N}\}

This is, we can define all even numbers as the set of all the multiples of 2

As for the odd numbers, we can always take every even number and sum one to each one. This is

O = \{ a\in \mathbb{Z} \setminus a=2.k+1,k\in\mathbb{N}_{0}\}

Note that k\in\mathbb{N}_{0}(the set of all natural numbers adding the zero) so that for k=0 then a=1

Now, given 2 odd numbers a and b we can write each one as follows:

a = 2k+1\\b = 2l+1\\k,l \in\mathbb{N}_{0}

And then if we multiply them with each other we obtain:

a.b = (2k+1).(2l+1)\\= 4kl+2k+2l+1\\= 2(2kl+k+l) + 1\\= 2k'+1 \\where\ k'=2kl+k+l

Then we have that a.b is also an odd number as we defined them.

6 0
3 years ago
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