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stira [4]
2 years ago
12

Which equation represents a line which is perpendicular to the line 5x + 2y = 12?

Mathematics
1 answer:
o-na [289]2 years ago
7 0

Answer:

<h2>          y = ²/₅ x - 3</h2>

Step-by-step explanation:

Changing to slope-intercept form:

5x + 2y = 12         {subtract 5x from both sides}

2y = -5x + 12         {divide both sides by 2}

y = -⁵/₂ x + 6

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y =-⁵/₂ x + 1    ⇒     m₁ =  -⁵/₂

-⁵/₂× m₂ = -1      ⇒   m₂ = ²/₅

So, any line perpendicular to 5x + 2y = 12 must have slope m =²/₅

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Norma-Jean [14]
Let d be the common difference between terms in the sequence \{a_n\}_{n\ge1}. Then

a_{19}=-58
a_{20}=a_{19}+d
a_{21}=a_{19}+2d
\implies-164=-58+2d\implies d=-53

The first term in the sequence, a_1, satisfies

a_2=a_1+d
a_3=a_1+2d
a_4=a_1+3d
...
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So the explicit formula for the n-th term in the sequence is

a_n=a_1+(n-1)d\implies a_n=896-53(n-1)
5 0
3 years ago
4 1/2 +1 3/5 (in the simplest form)
snow_lady [41]

6 1/10

Step-by-step explanation:

4 + 1/2+1+3/5

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8 0
3 years ago
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Aneli [31]

Answer:

x=−7

Step-by-step explanation:

(x+4)(2)−3(x+4)−3=0

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−x+−7=0

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