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Sladkaya [172]
3 years ago
10

Which statements are correct about the groups of the periodic table?

Physics
1 answer:
kolbaska11 [484]3 years ago
3 0
The have the same number of electron shells
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This problem has been solved!See the answerCommunication with submerged submarines via radio waves is difficult because seawater
mash [69]

Answer:

4000 km

Explanation:

as we know velocity of electromagnetic wave is c

c = 3 * 10^8 m/s

frequency  given (f) = 76 Hz

wavelength ?

using

c =fλ

λ =   \frac{c}{f}

λ =  \frac{3 * 10^8}{76}  ≈4000 km

 so final answer λ = 4000km

8 0
3 years ago
What is the frictional force between a box and the floor it is being pulled across if, the kinetic coefficient of friction is 0.
Artyom0805 [142]

If the pulling is done parallel to the floor with constant velocity, then the box is in equilibrium. In particular, the weight and normal force cancel, so that

<em>n</em> = 38 N

The friction force is proportional to the normal force by a factor of 0.27, so that

<em>f</em> = 0.27 (38 N) ≈ 10.3 N

and so the answer is D.

8 0
3 years ago
Convert the following statement to the language used by physicists, "I am cold, please turn on the heat."​
Vikki [24]

Answer:

Explanation:fog

6 0
3 years ago
If the car has a mass of 0.4 kg, the ratio of height to width of the ramp is 19/85, the initial displacement is 1.9 m, and the c
Rasek [7]

Answer:

final displacement lf  = 0.39 m

Explanation:

from change in momentum equation:

\delta p = m \sqrt(2g * y/x)* [\sqrt li + \sqrt lf]

given: m = 0.4kg, y/x = 19/85, li = 1.9 m,

\delta p = 1.27 kg*m/s.

putting all value to get the final displacement value

1.27 = 0.4\sqrt(2*9.81 *(19/85))* [\sqrt 1.9 + \sqrt lf]

final displacement lf  = 0.39 m

5 0
3 years ago
A sports car accelerates from rest for 5 seconds reaching a velocity of 23.0 m/s.
denis-greek [22]

Answer:

<h2>4.6 m/s²</h2>

Explanation:

The acceleration of an object given it's velocity and time taken can be found by using the formula

<h3>a =  \frac{v - u}{t}  \\</h3>

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

Since the body is from rest u = 0

From the question we have

a =  \frac{23 - 0}{5}  =  \frac{23}{5}  \\

We have the final answer as

<h3>4.6 m/s²</h3>

Hope this helps you

4 0
3 years ago
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