Question

Find the distance from N to T.

Answer 1

Answer:

The distance from N to T is :  $\sqrt{29}$   or   (square root of 29)

Step-by-step explanation:

From the given the diagram

• N(-2, -1)

• T(3, 1)

$\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$\mathrm{The\:distance\:between\:}\left(-2,\:-1\right)\mathrm{\:and\:}\left(3,\:1\right)\mathrm{\:is\:}$

$=\sqrt{\left(3-\left(-2\right)\right)^2+\left(1-\left(-1\right)\right)^2}$

$=\sqrt{\left(3+2\right)^2+\left(1+1\right)^2}$

$=\sqrt{5^2+\left(1+1\right)^2}$

$=\sqrt{5^2+2^2}$

$=\sqrt{25+4}$

$=\sqrt{29}$

Therefore, the distance from N to T is :  $\sqrt{29}$   or   (square root of 29)