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Nataliya [291]
3 years ago
8

A bag of candy contains 2 pieces of bubble gum, 4 jolly ranchers, and 10 tootsie rolls . what is the probability of reaching int

o the bag and choosing either a peice of bubble gum or a tootsie roll?
Mathematics
1 answer:
alexgriva [62]3 years ago
6 0
Total = 2 + 4 + 10 = 16

Bubble Gums and Tootsie Roll = 2 + 10 = 12

P(Bubble Gums and Tootsie Roll) = 12/16 = 3/4
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Find the zero of f(x) = x^5-12x^2+32x
Alexeev081 [22]
The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,

</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)

By the zero product theorem, (x-8)=0 or (x-4)=0 which means 
x=8 or x=4.

So the zeroes of f(x) are S={4,8}</span>
8 0
3 years ago
Given: f(x) = 3x + 2 and g(x) = 2x - 4
likoan [24]

In f(x) = 3x + 2, the x is being represented in the function. So, if we replace the x with the g(x) functions, we get:

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3 0
3 years ago
Read 2 more answers
12^13–12^12+12^11 is divisible by 7 and 19.
fiasKO [112]

Answer:

The statement is true

Step-by-step explanation:

The question is as following :

12^{13}-12^{12}+12^{11} is divisible by 7 and 19, true or false?

The given expression is 12^{13}-12^{12}+12^{11}

Take 12^{11} as a common

12^{13}-12^{12}+12^{11} = 12^{11}*(12^2-12^1+12^0)\\= 12^{11} *(144-12+1)\\=12^{11} * 133\\= 12^{11} * 7 * 19

So, 12^{11} * 7 * 19 divided 7 = 12^{11} * 19

And 12^{11} * 7 * 19 divided 19 = 12^{11} * 7

12^{13}-12^{12}+12^{11} is divisible by 7 and 19 (<u>True</u>)

8 0
2 years ago
X = 8 – 2y x + 3y = 12 What value of x satisfies the system of equations?
lora16 [44]

Answer: its 0 of 4 you can pick but i think its 4

Step-by-step explanion: i am not good at explaning this math but i know the answer

8 0
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Which number can each term of the equation be multiplied by to eliminate the fractions before solving?
DiKsa [7]

Answer:

12

Hope it helps

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3 years ago
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