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Fittoniya [83]
3 years ago
5

The mean temperature for the first 7 days in January was 6 °C.

Mathematics
1 answer:
serious [3.7K]3 years ago
7 0
That is the answer for the mean

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There are about 10^24 stars in the universe. Each galaxy has approximately the same number of stars as the Milky Way Galaxy. Abo
maks197457 [2]

Answer:

10^{13} galaxies.

Step-by-step explanation:

There are about 10^{24} stars in the universe.

The Milky Way galaxy10 * 10^{10} stars.

All we need to do to find the number of galaxies is to divide the total number of stars in the universe by the number of stars in the Milky Way:

Number of galaxies = (Number of stars in the universe) / (Number of stars in the Milky Way)

Number of galaxies = \frac{10^{24}}{10 * 10^{10}}

N = \frac{10^{24}}{10^{11}}

N = 10^{24 - 11} = 10^{13}

The number of galaxies in the universe is approximately 10^{13}.

7 0
3 years ago
Please help me out! And show your work :)) <3
8_murik_8 [283]

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Step-by-step explanation:

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3 0
3 years ago
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Which expression is equivalent to StartFraction (3 m Superscript negative 2 Baseline n) Superscript negative 3 Baseline Over 6 m
Dovator [93]

Option a: \frac{m^{5} }{162n} is the equivalent expression.

Explanation:

The expression is \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } where m\neq 0, n\neq 0

Let us simplify the expression, to determine which expression is equivalent from the four options.

Multiplying the powers, we get,

\frac{3^{-3}m^{6} n^{-3}}{6mn^{-2} }

Cancelling the like terms, we have,

\frac{3^{-3}m^{5} n^{-1}}{6 }

This equation can also be written as,

\frac{m^{5}}{3^{3}6 n^{1} }

Multiplying the terms in denominator, we have,

\frac{m^{5} }{162n}

Thus, the expression which is equivalent to \frac{(3m^{-2} n)^{-3}}{6mn^{-2} } is \frac{m^{5} }{162n}

Hence, Option a is the correct answer.

8 0
3 years ago
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We have the slope m = (6-3)/(4-1) = 3/3 = 1;
Then, y - 3 = 1·( x - 1);
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3 years ago
43. What is the translation rule to map AHIJ to AH ! J'?<br> 11<br> H
lutik1710 [3]
Left 4. Or x-4 because the way it moves
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3 years ago
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