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Fittoniya [83]
3 years ago
5

The mean temperature for the first 7 days in January was 6 °C.

Mathematics
1 answer:
serious [3.7K]3 years ago
7 0
That is the answer for the mean

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10
timama [110]

Answer:

25π units^2

Step-by-step explanation:

The shape is a quarter circle with radius 10 units.

area of circle = πr^2

area of a quarter circle = (1/4)π(10 units)^2

area = 25π units^2

5 0
3 years ago
Write the sum using summation notation assuming the suggested pattern continues<br> 9-18+36-72
IgorC [24]
I think it is 45 sorry if its wrong
5 0
3 years ago
Read 2 more answers
Can someone please help me with this question?<br><br> Find the value of c-5 when c=14
vlada-n [284]
1) C-5
2)14-5
3)9=The value!
I hope this helps!
3 0
3 years ago
Of all the people applying for a certain​ job, 80% are qualified and 20​% are not. The personnel manager claims that she approve
motikmotik

Answer:

69.23% probability that a person is not qualified if he or she was not approved by the manager.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes:

In this problem, we have these following probabilities:

80% probability that a person is qualified

20% probability that a person is not qualified.

90% probability that a qualified person is approved.

10% probability that a qualified person is not approved.

10% probability that an unqualified person is approved.

90% probability that an unqualified person is not approved.

Find the probability that a person is not qualified if he or she was not approved by the manager.

Desired outcomes

Unqualified and not approved.

20% are not qualified. Of those, 90% were not approved. So

0.9*0.2 = 0.18

Total outcomes:

Qualified and not approved or unqualified and not approved.

80% are qualified. Of those, 10% were not approved

20% are not qualified. Of those, 90% were not approved. So

0.8*0.1 + 0.9*0.2 = 0.26

Probability

P = \frac{0.18}{0.26} = 0.6923

69.23% probability that a person is not qualified if he or she was not approved by the manager.

7 0
3 years ago
If x2 + kx + 18 is factorable, what are the possible values of k?
sergeinik [125]
Assume that x² + kx + 18 if factorable.

The factors of 18 are
(1 x 18); (2 x 9); (3 x 6).

If we use (1, 18) as factors, then
(x - 1)(x - 18) = x² - 19x + 18 => k= -19
or
(x + 1)(x + 18) =  x² + 19x + 18  => k = 19

If we use (2,9) as factors, then
(x - 2)(x - 9) = x² - 11x + 18  => k = - 11
or
(x + 2)(x + 9) = x² + 11x + 18  => k = 11

If we use (3, 6) as factors, then
(x - 3)(x - 6) = x² - 9x + 18  => k = - 9
or
(x + 3)(x + 6) = x² + 9x + 18  => x = 9

Answer:
The possible values of k are -9,+9, -11, +11, -19, +19.

5 0
3 years ago
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