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dezoksy [38]
3 years ago
10

Write 14/√2 + √50 in the form b√2 where b is an integer.

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer:

12

Step-by-step explanation:

14/√2 +√50= 14*√2/√2*√2+ √25*2= 7√2+5√2= 12√2

12√2= b√2

b=12

kifflom [539]3 years ago
3 0

Answer:

12 \sqrt{2}

Step-by-step explanation:

Taking the terms one at a time,

\frac{14}{ \sqrt{2} }  \\   \frac{14 *  \sqrt{2} }{ \sqrt{2} *  \sqrt{2}  }  \\   \frac{14  \sqrt{2} }{2}  \\  7 \sqrt{2}

\sqrt{50} \\  \sqrt{25 * 2} \\  \sqrt{25}*  \sqrt{2}    \\ 5 *  \sqrt{2}   \\ 5 \sqrt{2}

Adding the terms, you have;

7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}

Hope it helps!

I'm out!

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olga nikolaevna [1]
Shirt: $50
Coat: $113

$50+ $113= $163

The coat costs $163, hope this helps!
7 0
3 years ago
The price in dollars of a stereo system is given by p(q) = (1000/q2)+1000 where q represents the demand of the product.
elena-14-01-66 [18.8K]

Answer:

  a) r(q) = 1000(q +1/q)

  b) r'(q) = 1000(1 -1/q^2)

  c) r'(10) = 990

Step-by-step explanation:

a) Revenue is the product of quantity and price:

  r(q) = q·p(q) = q(1000(1 +1/q^2))

  r(q) = 1000(q + 1/q)

__

b) The derivative is ...

  r'(q) = 1000(1 -1/q^2)

__

c) The derivative evaluated for q=10 is ...

  r'(10) = 1000(1 -1/10^2) = 1000(0.99)

  r'(10) = 990

5 0
3 years ago
A student claims that 8^3 • 8^5 is greater than 1 explain whether the student is correct or not
WARRIOR [948]
In order to answer this question the parts must be broken down: 8^3 is 8*8*8 which equals 512 and 8^5 is 8*8*8*8*8 which equals 32761. 512*32761 equals 16777216. 167772176 is greater than 1.
7 0
4 years ago
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I'm saving up for Ariana Grande meet & greet tickets (which are like $1000 lol)
mr_godi [17]

Answer:

Maybe make a  Y_O_U_T_U_B_E channel

Step-by-step explanation:

5 0
3 years ago
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What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
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