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dezoksy [38]
2 years ago
10

Write 14/√2 + √50 in the form b√2 where b is an integer.

Mathematics
2 answers:
fenix001 [56]2 years ago
6 0

Answer:

12

Step-by-step explanation:

14/√2 +√50= 14*√2/√2*√2+ √25*2= 7√2+5√2= 12√2

12√2= b√2

b=12

kifflom [539]2 years ago
3 0

Answer:

12 \sqrt{2}

Step-by-step explanation:

Taking the terms one at a time,

\frac{14}{ \sqrt{2} }  \\   \frac{14 *  \sqrt{2} }{ \sqrt{2} *  \sqrt{2}  }  \\   \frac{14  \sqrt{2} }{2}  \\  7 \sqrt{2}

\sqrt{50} \\  \sqrt{25 * 2} \\  \sqrt{25}*  \sqrt{2}    \\ 5 *  \sqrt{2}   \\ 5 \sqrt{2}

Adding the terms, you have;

7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}

Hope it helps!

I'm out!

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Kisachek [45]

Answer:

The slope intercept form: y = - 5x + 7

Step-by-step explanation:

The equation of line f is y − 9 = -5(x + 7)

You need to find the slope of line f

y - 9 =  -5(x + 7)

In point slope form: y - y1 = m(x - x1) where m = slope

In the line f, slope m = -5

Parallel lines, slope is the same so slope of line g is also equal - 5

Line g passes through (3, - 8) so equation in point slope form:

y + 8 = -5(x - 3)

y + 8 = -5x + 15

y = -5x + 7    <-----this is slope intercept form

5 0
3 years ago
The altitude of a triangle is 1cm shorter than the base. If the area of the triangle is 15cm2, calculate the altitude.
WITCHER [35]

Answer:

5 cm

Step-by-step explanation:

We khow that the altitude of this triangle is 1cm shorter than the base

  • Let H be our altitude and B our base and A the area of the triangle
  • A= (B*H)/2 ⇒ 15=(B*H)/2
  • H is 1cm shorter than B ⇒ B=H+1
  • H*(H+1)/2=15 ⇒ H*(H+1)=30⇒ H²+H=30⇒H²+H-30+0

that's a quadratic equation . Let's calculate the dicriminant .

Let Δ be the dicriminant

  • a=1
  • b=1
  • c= -30
  • Δ=b²-4*a*c = 1²-4*1*(-30)=1+4*30=121≥0
  • Δ≥0⇔ that we have two solutions x and y
  • x= (-1-\sqrt{121})/2= (-1-11)/2= -6
  • y= (-1+\sqrt{121})/2= 10/2 = 5

We have a negative value and a positive one

The altitude is a distance so it can't be negative

H= 5cm

6 0
3 years ago
Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

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3 years ago
A linear set of points with a unique starting point and extending infinitely in one direction what term matches the definition?
bija089 [108]

Answer:- Option A "ray" is the right term which matches with the definition.


Explanation:-

A ray is a line that has one fixed endpoint, and extends infinitely along the line from the fixed endpoint.

Therefore, the term which matches with the given definition is "ray".

Thus A linear set of points with a unique starting point and extending infinitely in one direction is called a ray.


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What is the equation of the line that passes through the point (-4,8) and has a slope of -1/4
iragen [17]

Answer:

Step-by-step explanation:

When a slope of a line and a point passing through it is given then we use slope - one point form to determine the equation of the line.

It is given by:

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where $m$ is the slope of the line and

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Here, $ m = \frac{-1}{4} $ and $ (x_1,y_1) = (-4,8) $

Substituting in the equation:

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$ \implies 4y - 32 = -x - 4 $

$ \implies x + 4y - 28 = 0 $

3 0
2 years ago
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