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dezoksy [38]
3 years ago
10

Write 14/√2 + √50 in the form b√2 where b is an integer.

Mathematics
2 answers:
fenix001 [56]3 years ago
6 0

Answer:

12

Step-by-step explanation:

14/√2 +√50= 14*√2/√2*√2+ √25*2= 7√2+5√2= 12√2

12√2= b√2

b=12

kifflom [539]3 years ago
3 0

Answer:

12 \sqrt{2}

Step-by-step explanation:

Taking the terms one at a time,

\frac{14}{ \sqrt{2} }  \\   \frac{14 *  \sqrt{2} }{ \sqrt{2} *  \sqrt{2}  }  \\   \frac{14  \sqrt{2} }{2}  \\  7 \sqrt{2}

\sqrt{50} \\  \sqrt{25 * 2} \\  \sqrt{25}*  \sqrt{2}    \\ 5 *  \sqrt{2}   \\ 5 \sqrt{2}

Adding the terms, you have;

7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}

Hope it helps!

I'm out!

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Which function has a greater rate of change? Function A: x 1.5 2.5 3.5 4.5 5.5 y 5 0 –5 –10 –15 Function B: y = –4.5x + 15 Funct
expeople1 [14]

Answer:

Function A has a rate of change of -5 and Function B has a rate of change of -4.5, so Function B has a greater rate of

Step-by-step explanation:

Function A:

\begin{array}{cccccc}x & {1.5} & {2.5} & {3.5} & {4.5} & {5.5} \ \\ y & {5} & {0} & {-5} & {-10} & {-15} \ \end{array}

Function B:

y = -4.5x + 15

Required

Which has a greater rate of change

The rate of change of function A is calculated as thus:

m = \frac{y_2 - y_1}{x_2 - x_1}

Where:

(x_1,y_1) = (1.5,5)

(x_2,y_2) = (2.5,0)

So, we have:

m = \frac{0-5}{2.5 - 1.5}

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m = -5

For function B

The general function is:

y = mx + b

Where

m is the rate of change

By comparing y = mx + b to y = -4.5x + 15

m = -4.5

So, we have that:

Function A has a rate of -5; function B has a rate of -4.5.

By comparison: -4.5 is greater than 5

Hence, function B has a greater rate.

4 0
3 years ago
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