i. 171
ii. 162
iii. 297
Solution,
n(U)= 630
n(I)= 333
n(T)= 168
i. Let n(I intersection T ) be X
<h3>ii.
n(only I)= n(I) - n(I intersection T)</h3><h3>
= 333 - 171</h3><h3>
= 162</h3>
<h3>
iii. n ( only T)= n( T) - n( I intersection T)</h3><h3>
= 468 - 171</h3><h3>
= 297</h3>
<h3>
Venn- diagram is shown in the attached picture.</h3>
Hope this helps...
Good luck on your assignment...
Answer:
1/20
Step-by-step explanation:
Step 1: Write the given number as the numerator and place 1 in the denominator right below the decimal point followed by the number of zeros required accordingly.
In this case, 0.05 has two numbers after the decimal, so, we place 100 in the denominator and remove the decimal point. This will make it 5/100
Step 2: Then, this fraction can be simplified. 5/100 = 1/20
Thus, 0.05 as a fraction is written as 1/20
Answer:
see below
Step-by-step explanation:
Write an expression:
x + 1 = 1.011
solve the expression:
subtract 1 on left n right of the = sign
x + 1 - 1 = 1.011 - 1
x = 0.011
Round to nearest hundredth
x = 0.01
The solution is solving an algebra equation with the ans rounded to the hundredth.
Answer:
B
Step-by-step explanation:
I just took the test.
Answer:
1040 students will attend
Step-by-step explanation:
Out of 80 students, 52 will attend
80/52 = 1600/ x
x=1040
