<span>The bacteria in a certain culture double every 7.1 hours.
The culture has 6,500 bacteria at the start. How much after 4 hrs
:
Using the formula: A = Ao*2^(t/d) where
A = amt after t time
Ao = initial amt (t=0)
t = time of action
d = doubling time of the bacteria
;
A = 6500*2^(4/7.1)
A = 6500 * 1.4777
A = 9605 bacteria after 4 hrs</span>
Answer:
7234.56
Step-by-step explanation:
Using 3.14 as pi the answer is
I'm pretty sure its 127.8
ANSWER
The value of a and b are:

EXPLANATION
The expression given to us is

We square both sides of the equation to obtain

We now find the prime factorization of 648 to obtain,

We now compare the exponents on both sides of the equation to obtain,

Therefore the correct option is C