Answer:
a) 
b) 
c) the points of the form (x, -x) for x≠0
Step-by-step explanation:
a)
If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be
On one hand we have,
On the other hand,
So
b)
The domain of definition of F is
i.e., all the plane X-Y except the (0,0)
c)
Here we want to find all the points such that
where k is a real number other than 0.
But this means
So, all the points in the line y = -x except (0,0) are parallel to the vector field F, that is, the points (x, -x) with x≠ 0
The answer is the first data set because remember, an outlier is a number in a data set that is extremely far away from all of the other numbers.
You can easily tell which one is the outlier, the first data set's outlier is 13, because it is was placed so far away from the other data points.
We know that the first data set is correct because all of the other data sets have numbers that are clustered together.
~Hope I helped!~
-2x + 6y = -34
-x + 3y = -17
x = 3y +17
Sub this into 1st eqn
5(3y + 17) + 2y = 21
15y + 85 + 2y =21
17y = -64
y = -3.7647 (to 5 sig. fig.)
y = -3.8 (to nearest tenth)
Sub y = -3.7647 into 2nd eqn
x = 3(-3.7647) +17
x = 5.7 (to nearest tenth)
You find the GCF of 250 and 363 by factoring. 250 = 5^4 * 2. 363 = 3 * 11^2, and they have no common factors, so 250/363 is already in its simplest form!
The decimal form for 5.63 x 10^-6 is 0.00000563
