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Gennadij [26K]
3 years ago
13

Estimate each product. 2/9 of 88

Mathematics
1 answer:
kakasveta [241]3 years ago
4 0
<span>19.55
</span>That's what I have gotten.
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I need help on on which one is the answer
ch4aika [34]

Answer:

{yI -5\leq y \leq -1}

Step-by-step explanation:

7 0
3 years ago
How do I solve it?? I need help I don't understand how to go this.
Mashcka [7]
The answer is $1,908 

1. Find out 6% of 40,000 is 108. Now you have your sales commission for the month
2. Add 108 onto 1,800 to get your complete month's pay
7 0
3 years ago
Hamburger heaven is having a lunch special where customers buy one 3/4 pounds cheese burger and get one free if they set aside 1
Yuri [45]

Answer:

49

Step-by-step explanation:

49 hamburguers (of 3/4 pound)

Step-by-step explanation:

3/4 pound is equal to 0.75 pound

37 1/3 pounds of meat is equal to

37 + 1/3 pound =  37.3333 pounds

To find how much hamburguers can be made, we need to divide

37.3333 pounds/ 0.75 pounds

37.3333 pounds/ 0.75 pounds = 49.777777

(We need to round to the lowest number)

This means that 49 hamburguers could be made

Plz mark brainliest

5 0
3 years ago
Compare the rates of change of the following items.
vladimir1956 [14]

Answer:

C

Step-by-step explanation:

the equation of relationship between x and y in item ll is: y = -x -3

the rate of change of it is -1 that is equal to the rate of change of items l.

4 0
2 years ago
If the sum of any two number is 20 and difference is 10 find the numbers​
Tanya [424]

"The sum of two numbers is 20" can be translated mathematically into the equation:

x + y = 20.

"... and their difference is 10" can be translated mathematically as:

x - y = 10

We can now find the two unknown numbers, x and y, because we now have a system of two equations in two unknowns, x and y. We'll use the Addition-Subtraction Method, also know as the Elimination Method, to solve this system of equations for x and y by first eliminating one of the variables, y, by adding the second equation to the first equation to get a third equation in just one unknown, x, as follows:

Adding the two equations will eliminate the variable y:

x + y = 20

x - y = 10

-----------

2x + 0 = 30

2x = 30

(2x)/2 = 30/2

(2/2)x = 15

(1)x = 15

x = 15

Now, substitute x = 15 back into one of the two original equations. Let's use the equation showing the sum of x and y as follows (Note: We could have used the other equation instead):

x + y = 20

15 + y = 20

15 - 15 + y = 20 - 15

0 + y = 5

y = 5

CHECK:

In order for x = 15 and y = 5 to be the solution to our original system of two linear equations in two unknowns, x and y, this pair of numbers must satisfy BOTH equations as follows:

x + y = 20 x - y = 10

15 + 5 = 20 15 - 5 = 10

20 = 20 10 = 10

Therefore, x = 15 and y = 5 is indeed the solution to our original system of two linear equations in two unknowns, x and y, and the product of the two numbers x = 15 and y = 5 is:

xy = 15(5)

xy = 75

6 0
3 years ago
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