Triangle ABC is similar to triangle APQ. They have corresponding line segments. Line segment PQ corresponds to BC.
Answer:
A. 264
Step-by-step explanation:
First, we have to find the value of x. Then we can use that to find the required arc measure.
∠M = (1/2)(arc KN - arc LN)
60 = (1/2)((18x -6) -(5x +17)) = (1/2)(13x -23) . . . . substitute and simplify
120 = 13x -23 . . . . . . . multiply by 2
143 = 13x . . . . . . . . . . add 23
11 = x . . . . . . . . . . . . . . divide by 13
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arc KNL = (arc KN) + (arc NL) = (18x -6) +(5x +17) = 23x +11
= 23·11 +11
arc KNL = 264 . . . . degrees
Answer:
The standard form of line is
Step-by-step explanation:
we are given a line
slope=3
so,
y-intercept of -2
so,
now, we can use slope-intercept form of line
now, we can plug values
we can write it in standard form of line
we can subtract both sides by 3x
So, the standard form of line is
Given a right triangle with hypothenus of measure 34, the side opposite the angle θ of measure 30, and the side adjacent the angle theta of measure 16.
If you can get me some numbers this would be easier
however there's r= radius
h=height
I'm not fully understanding this
