Answer:
please show the full question and probability and also don't be nervous about it or panic search in goohle
Answer:
12
Step-by-step explanation:
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Given:
Two brothers are sharing a certain sum of money in the ratio
.
The largest share was Gh¢500.00.
To find:
The total amount shared between them.
Solution:
It is given that, two brothers are sharing a certain sum of money in the ratio
.
First we need to make the denominators common.
![Ratio=\dfrac{2\times 5}{3\times 5}:\dfrac{3\times 3}{5\times 3}](https://tex.z-dn.net/?f=Ratio%3D%5Cdfrac%7B2%5Ctimes%205%7D%7B3%5Ctimes%205%7D%3A%5Cdfrac%7B3%5Ctimes%203%7D%7B5%5Ctimes%203%7D)
![Ratio=\dfrac{10}{15}:\dfrac{9}{15}](https://tex.z-dn.net/?f=Ratio%3D%5Cdfrac%7B10%7D%7B15%7D%3A%5Cdfrac%7B9%7D%7B15%7D)
![Ratio=10:9](https://tex.z-dn.net/?f=Ratio%3D10%3A9)
So, the two brothers are sharing a certain sum of money in the ratio 10:9.
Let the shares of two brothers are 10x and 9x respectively. So, the larger share is 10x.
It is given that the largest share was Gh¢500.00.
![10x=500](https://tex.z-dn.net/?f=10x%3D500)
![x=\dfrac{500}{10}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B500%7D%7B10%7D)
![x=50](https://tex.z-dn.net/?f=x%3D50)
Now, the total amount shared between them is:
![Total=10x+9x](https://tex.z-dn.net/?f=Total%3D10x%2B9x)
![Total=19x](https://tex.z-dn.net/?f=Total%3D19x)
![Total=19(50)](https://tex.z-dn.net/?f=Total%3D19%2850%29)
![Total=950](https://tex.z-dn.net/?f=Total%3D950)
Therefore, the total amount shared between them is Gh¢950.00.