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2 years ago

13

Tyler's brother earns $12 per hour. The store offers him a raise - a 5% increase per hour. After the raise, how much will Tyler'

s brother make per hour?

1 answer:

Natali [406]2 years ago

7 0

Answer: $12*0.05=$0.60. Then, add this amount to his current hourly rate. So he now makes $12.60.

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The value of U.S exports to China increased from $1480 million in 2011 to $2768 million in 2012. What was the percentage increas

loris [4]

Answer: Percentage increase is <em><u>87.02%.</u></em>

Explanation: Percentage increase is calculated by subtracting the value in 2012 from the value of exports in 2011 and then dividing it by the value in year 2011.

a. Subtract value in 2012 from value in 2011

b. Divide the answer in part a by value in 2011.

c. Multiply the answer in part b by 100.

We have the percentage increase.

<u>mark brainliest pls </u>

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2 years ago

3^3x3^3=3^5x3^x<br> Using exponent rules

gayaneshka [121]

The answer to the problem is x=0,1

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%2036x%20%2B%20324%20%3D%20%28x%20%2B%20m%29%5E%7B2%7D%20" id="TexFormula1

nasty-shy [4]

Answer:

B. 18

Step-by-step explanation:

$x^{2} + 36x + 324 = (x + m)^{2}$

$(x+18)^{2}= (x + m)^{2}$

$\cancel x+18= \cancel x + m$

$18= m$

5 0

2 years ago

Read 2 more answers

PLEASE HELP ME ON THIS AND SHOW UR WORK<br> THX

swat32

When an exponential function is given as
f(x)=ab^x, and
knowing that b^0=1, that means that
f(0)=ab^0=a value of function when x=0, or the initial value.
In the case of
f(x)=20.b^x, f(0)=20.b^0 = 20 (initial value)

If b=1.2, then the hourly growth rate is (1.2-1)=0.2=20%.
If b=1.85, then the hourly growth rate is (1.85-1)=0.85=85%.

4 0

3 years ago

równanie zmiany prędkość autokaru poruszającego się po prostym odcinku szosy i rozpoczynającego hamowanie od szybkości 20m/s ma

Rasek [7]

Answer:

s = 22.5 m

Step-by-step explanation:

the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.

v (t) = 25 - 5 t

at t = 0 , v = 20 m/s

Let the distance is s.

$s =\int v(t) dt\\\\s =\int (25 - 5t)dt\\\\s= 25 t - 2.5 t^2 \\$

Let at t = t, the v = 20

So,

20 = 25 - 5 t

t = 1 s

So, s = 25 x 1 - 2.5 x 1 = 22.5 m

3 0

2 years ago