Identify the domain and range of the relation. Represent the relation with a
1 answer:
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Answer:
surface area of cube time
Step-by-step explanation:
given data
new volume = 10 time original volume
to find out
what factor surface area change
solution
we consider here side of cube is a
and volume is V
we consider here a is 2
then volume will be v1 = a³ = 2³ = 8
and surface area = 6a² = 6(2)² = 24 ..........1
so if volume increase 10 time
than
V = 10 × v1
a³ = 10 × 8
a³= 80
a = 2 × ∛10
and
surface area increase here
surface area = 6a²
surface area = 6( 2 × ∛10 )²
surface area = 24 × ............2
so from equation 1 and 2
surface area / surface area = 24 × / 24
surface area =
so here surface area of cube will be time