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nikklg [1K]
3 years ago
11

Janie is analyzing a quadratic function f(x) and a linear function g(x). Will they intersect?

Mathematics
2 answers:
o-na [289]3 years ago
6 0

Answer:

D

Step-by-step explanation:

UkoKoshka [18]3 years ago
3 0

Answer:

Option (D) is correct.

No, They will not intersect.

Step-by-step explanation:

Given Points for g(x), (1,2) , (2,4) and (3,6)

Since g is a linear function then it must be in form of  g(x) = mx +c where, c is constant and m is slope.

We first calculate the slope using,

m=\frac{y_2-y_1}{x_2-x_1}

Here, consider x_1=1 , x_2=2 , y_1=2, y_2=4

Substitute above, we get slope as,

m=\frac{4-2}{2-1}=2

Thus, equation becomes g(x) = 2x + c  ...(1)

For c plug the values  in (1),

(1,2) ⇒ 2= 2 + c ⇒  c = 0

Thus, Equation of G(x) is 2x.

When we plot it it do not intersect f(x).

Thus, Option (D) is correct.

No, They will not intersect.




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F(x)=2x-10

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x=2y-10

x+10=2y-10+10 (add both sides by 10)

2y=x+10

2y/2=x+10/2 (divide both sides by 2)

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<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

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