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Jobisdone [24]
2 years ago
10

Can the values be added or subtracted? If one value needs to be converted to another, describe the conversion.

Mathematics
1 answer:
vaieri [72.5K]2 years ago
8 0
Okie, the terms are similar in that they both have inches, but they are in different forms. The first has inches to the 2nd power. This is a unit for area. The second has the units of inches to the 3rd power. This is a unit of volume. To convert from area to volume, you would need a conversion but it usually would be from a problem with certain values. Ex. Think of a cube, the 2 sides multiplied would be area and third multiplied in would be volume. If you are adding an area to a volume, you would need to know of which since you cannot change volume magically to area or area magically to volume if you do not know the details of the problem. The answer is A; I hope this helps :-)
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What is the domain of g?
Mrac [35]

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Solution. The domain of g(x) consists of all real numbers except x = 32, since that input value would cause us to divide by 0. Likewise, the domain of f consists of all real numbers except 1. So we need to exclude from the domain of g(x) that value of x for which g(x) = 1.

Step-by-step explanation:

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Given two vectors A=2i+3j+4k,B=i-2j+3k find the magnitude and direction of sum<br>(physics question)
Law Incorporation [45]

Answer:

Magnitude =\sqrt{59} \\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}}

Step-by-step explanation:

A=2i+3j+4k

B=i-2j+3k

Sum of the vectors:

A + B = 2i+3j+4k + i-2j+3k = 3i + j + 7k

Magnitude =\sqrt{3^2 + 1^2+ 7^2} \\\\Magnitude =\sqrt{9+1+49} \\\\Magnitude =\sqrt{59}

Direction of the sum of the vectors:

\widehat{A + B} =\frac{\overrightarrow{A + B}}{Magnitude\: of \:\overrightarrow{A + B}} \\\\\widehat{A + B} =\frac{3i + j + 7k}{\sqrt {59}} \\\\\widehat{A + B} =\frac{3}{\sqrt {59}} i +\frac{1}{\sqrt {59}} j+\frac{7}{\sqrt {59}} k\\\\Direction \: of \: \overrightarrow{A + B} = \frac{3}{\sqrt {59}} , \:\frac{1}{\sqrt {59}} , \:\frac{7}{\sqrt {59}} \\\\

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